Verbal Reasoning - Classification - Discussion
Discussion Forum : Classification - Section 12 (Q.No. 6)
Directions to Solve
In each of the following questions, some groups of letters are given, all of which, except one, share a common similarity while one is different. Choose the odd one out.
6.
Choose the odd one out.
Answer: Option
Explanation:
In all other groups, the second, third and first letters are alternate letters of the alphabet in order.
Discussion:
3 comments Page 1 of 1.
Homan said:
9 years ago
Also, the difference between the 1st and 2nd alphabet is 4 and 2nd and 3rd alphabet is 2.
And this pattern is not followed in option B.
And this pattern is not followed in option B.
Varun said:
8 years ago
Yes, @Homan.
B is wrong.
B is wrong.
Jahnavi said:
7 years ago
In the first one; R & T r alternate similarly T & V r alternate.
Similarly, in 3rd 4th & 5th W, D, K are alternates of U, B & I.
But the rule isn't followed in the second one & hence 2nd is the odd one out.
Similarly, in 3rd 4th & 5th W, D, K are alternates of U, B & I.
But the rule isn't followed in the second one & hence 2nd is the odd one out.
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