Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 31)
31.
A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ?
Answer: Option
Explanation:
We have : A = 3B ...(i) and
C - 4 = 2 (A - 4) ...(ii)
Also, A + 4 = 31 or A= 31-4 = 27.
Putting A = 27 in (i), we get: B = 9.
Putting A = 27 in (ii), we get C = 50.
Discussion:
6 comments Page 1 of 1.
Lakshminaraasimha said:
7 years ago
Hence, in 4 years time a=31.
so,a=31-4=27.
a=3b i,e b=9.
Again 4 years ago 27-3=23,
c=2a i.e c=2*23=46,
Present age of c=46+4=50,
a=23, b=9, c=50.
so,a=31-4=27.
a=3b i,e b=9.
Again 4 years ago 27-3=23,
c=2a i.e c=2*23=46,
Present age of c=46+4=50,
a=23, b=9, c=50.
Ramadhin said:
8 years ago
B is the correct answer. I agree.
Sharma ji ka beta said:
8 years ago
A is the correct answer.
Ravina said:
10 years ago
C-4 = 2(27-4).
C-4 = 46.
C = 50.
So option B is correct.
C-4 = 46.
C = 50.
So option B is correct.
Anil said:
1 decade ago
Yes you are correct C age is twice when A age 4 years ago.
so, C = 2(A-4).
C = 2(27-4).
C = 46.
so, C = 2(A-4).
C = 2(27-4).
C = 46.
Imran Ali said:
1 decade ago
In my opinion answer should be A, 50 is not current age of c, it may be 46, if I'm wrong please explain.
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