Verbal Reasoning - Arithmetic Reasoning - Discussion

Discussion :: Arithmetic Reasoning - Section 1 (Q.No.31)

31. 

A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ?

[A]. 9, 46
[B]. 9, 50
[C]. 10, 46
[D]. 10, 50

Answer: Option B

Explanation:

We have : A = 3B ...(i) and

C - 4 = 2 (A - 4) ...(ii)

Also, A + 4 = 31 or A= 31-4 = 27.

Putting A = 27 in (i), we get: B = 9.

Putting A = 27 in (ii), we get C = 50.


Imran Ali said: (Sep 17, 2014)  
In my opinion answer should be A, 50 is not current age of c, it may be 46, if I'm wrong please explain.

Anil said: (Feb 22, 2015)  
Yes you are correct C age is twice when A age 4 years ago.

so, C = 2(A-4).
C = 2(27-4).
C = 46.

Ravina said: (Sep 16, 2015)  
C-4 = 2(27-4).

C-4 = 46.

C = 50.

So option B is correct.

Sharma Ji Ka Beta said: (Jul 5, 2017)  
A is the correct answer.

Ramadhin said: (Dec 5, 2017)  
B is the correct answer. I agree.

Lakshminaraasimha said: (Jul 23, 2018)  
Hence, in 4 years time a=31.
so,a=31-4=27.
a=3b i,e b=9.

Again 4 years ago 27-3=23,
c=2a i.e c=2*23=46,
Present age of c=46+4=50,
a=23, b=9, c=50.

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