Verbal Reasoning - Arithmetic Reasoning - Discussion

Discussion :: Arithmetic Reasoning - Section 1 (Q.No.31)

31.

A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ?

 [A]. 9, 46 [B]. 9, 50 [C]. 10, 46 [D]. 10, 50

Explanation:

We have : A = 3B ...(i) and

C - 4 = 2 (A - 4) ...(ii)

Also, A + 4 = 31 or A= 31-4 = 27.

Putting A = 27 in (i), we get: B = 9.

Putting A = 27 in (ii), we get C = 50.

 Imran Ali said: (Sep 17, 2014) In my opinion answer should be A, 50 is not current age of c, it may be 46, if I'm wrong please explain.

 Anil said: (Feb 22, 2015) Yes you are correct C age is twice when A age 4 years ago. so, C = 2(A-4). C = 2(27-4). C = 46.

 Ravina said: (Sep 16, 2015) C-4 = 2(27-4). C-4 = 46. C = 50. So option B is correct.

 Sharma Ji Ka Beta said: (Jul 5, 2017) A is the correct answer.

 Ramadhin said: (Dec 5, 2017) B is the correct answer. I agree.

 Lakshminaraasimha said: (Jul 23, 2018) Hence, in 4 years time a=31. so,a=31-4=27. a=3b i,e b=9. Again 4 years ago 27-3=23, c=2a i.e c=2*23=46, Present age of c=46+4=50, a=23, b=9, c=50.