Discussion :: Arithmetic Reasoning - Section 1 (Q.No.11)
|Dasharath said: (Jan 7, 2012)|
|I didn't get this point explain be clearly.|
|Sujit Chowra said: (Jul 30, 2013)|
|Given A= B+3, and C = A+3.
C = B+3+3, C= B+6 here B = D So, 6 years older C than D.
|Sanjay said: (Jun 7, 2016)|
|I am not understanding this clearly.|
|What said: (Jun 27, 2016)|
|Not getting this. Can anyone help me to get it?|
|Gtaja said: (Jul 10, 2016)|
|I couldn't get this. Help me to understand this.|
|Chris said: (Dec 2, 2016)|
|Easiest way for me to solve this was by doing the following:
A - 3 = B and A + 3 = C, B = D. Let A = 14
14 - 3 = B, so B = 11, therefore D = 11 as B = D
14 + 3 = C, so C = 17. 17(C) - 11(D) = 6, therefore, C is 6 years older than D.
|Srikanth said: (Jan 22, 2017)|
|I didn't get it. Someone help me by the explanation.|
|Jamel Telesford said: (Jun 19, 2017)|
|Is there a way for you to do this with only one variable?|
|Jayanthi said: (Mar 20, 2018)|
both D and C are 6.
|Avani said: (Dec 15, 2019)|
|Assume a random number for A.
Let it be A = 10.
Then B will be 7 (A is 3 years older than B is given in question).
Then C will be 13 (A is younger than C by 3 Years is also given).
Since B = D. Find different between B and C.
ie, 13-7 = 6.
Hence we get the diff of C and D = 6.
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