Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 11)
11.
A is 3 years older to B and 3 years younger to C, while B and D are twins. How many years older is C to D?
Answer: Option
Explanation:
Since B and D are twins, so B = D.
Now, A = B + 3 and A = C - 3.
Thus, B + 3 = C - 3 
D + 3 = C-3 C - D = 6.
Discussion:
11 comments Page 1 of 2.
Ghussan Khalid said:
5 months ago
@All.
Here's my explanation for the solution.
> A is 3 years older to B
and [A is] 3 years younger to C (careful here, not to read B is 3 years younger than C)
So, A = 10 and B = 7
And A = 10 and C = 13.
Hence the difference between C and B (twin of D) is 13 - 7.
which is 6.
Here's my explanation for the solution.
> A is 3 years older to B
and [A is] 3 years younger to C (careful here, not to read B is 3 years younger than C)
So, A = 10 and B = 7
And A = 10 and C = 13.
Hence the difference between C and B (twin of D) is 13 - 7.
which is 6.
Avani said:
6 years ago
Assume a random number for A.
Let it be A = 10.
Then B will be 7 (A is 3 years older than B is given in question).
Then C will be 13 (A is younger than C by 3 Years is also given).
Since B = D. Find different between B and C.
ie, 13-7 = 6.
Hence we get the diff of C and D = 6.
Let it be A = 10.
Then B will be 7 (A is 3 years older than B is given in question).
Then C will be 13 (A is younger than C by 3 Years is also given).
Since B = D. Find different between B and C.
ie, 13-7 = 6.
Hence we get the diff of C and D = 6.
(2)
Jayanthi said:
7 years ago
A=B+3........(1)
A=B-3..........(2)
B=D...............(3)
B+3=B-3,
B=-3-3,
B=6,
6=D,
both D and C are 6.
A=B-3..........(2)
B=D...............(3)
B+3=B-3,
B=-3-3,
B=6,
6=D,
both D and C are 6.
Jamel Telesford said:
8 years ago
Is there a way for you to do this with only one variable?
(1)
Srikanth said:
9 years ago
I didn't get it. Someone help me by the explanation.
(1)
Chris said:
9 years ago
Easiest way for me to solve this was by doing the following:
A - 3 = B and A + 3 = C, B = D. Let A = 14
14 - 3 = B, so B = 11, therefore D = 11 as B = D
14 + 3 = C, so C = 17. 17(C) - 11(D) = 6, therefore, C is 6 years older than D.
A - 3 = B and A + 3 = C, B = D. Let A = 14
14 - 3 = B, so B = 11, therefore D = 11 as B = D
14 + 3 = C, so C = 17. 17(C) - 11(D) = 6, therefore, C is 6 years older than D.
Gtaja said:
9 years ago
I couldn't get this. Help me to understand this.
What said:
9 years ago
Not getting this. Can anyone help me to get it?
Sanjay said:
9 years ago
I am not understanding this clearly.
Sujit Chowra said:
1 decade ago
Given A= B+3, and C = A+3.
C = B+3+3, C= B+6 here B = D So, 6 years older C than D.
C = B+3+3, C= B+6 here B = D So, 6 years older C than D.
(1)
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