Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 39)
39.
A certain number of horses and an equal number of men are going somewhere. Half of the owners are on their horses' back while the remaining ones are walking along leading their horses. If the number of legs walking on the ground is 70, how many horses are there ?
Answer: Option
Explanation:
Let number of horses = number of men = x.
Then, number of legs = 4x + 2 x (x/2) = 5x.
So, 5X = 70 or x = 14.
Discussion:
11 comments Page 2 of 2.
Sherab said:
3 years ago
Here no Of horses and men is equal.
So, Let's say x
While half of the owner is on horses back and a half walking
So total legs on the ground is 70.
We know a horse has 4 legs and a man has 2 legs
So 4x + 2(x/2)= 70 (here x/2 is bcoz half of the men is on horse's back while only half is walking with horses).
5x = 70 .
x = 14 (horses and men).
So, Let's say x
While half of the owner is on horses back and a half walking
So total legs on the ground is 70.
We know a horse has 4 legs and a man has 2 legs
So 4x + 2(x/2)= 70 (here x/2 is bcoz half of the men is on horse's back while only half is walking with horses).
5x = 70 .
x = 14 (horses and men).
(2)
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