Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 2 (Q.No. 5)
5.
In a group of cows and hens, the number of legs are 14 more than twice the number of heads. The number of cows is
Answer: Option
Explanation:
Let the number of cows be x and the number of hens be y.
Then, 4x + 2y = 2 (x + y) + 14 
4x + 2y = 2x + 2y + 14 2x = 14 x = 7.
Discussion:
12 comments Page 1 of 2.
Jhanu said:
5 years ago
Then, How many hens are there?
Paimon Dkhar said:
7 years ago
According to Me;.
Here;
7cow x 4 legs =28legs.
7head X 2 =14 head (To make it twice the no of the head).
Therefore here I got;
28 legs and 14 heads.
Where the legs is 14 more than twice the no of the head.
The answer is 7.
Here;
7cow x 4 legs =28legs.
7head X 2 =14 head (To make it twice the no of the head).
Therefore here I got;
28 legs and 14 heads.
Where the legs is 14 more than twice the no of the head.
The answer is 7.
Selvam said:
7 years ago
Agree @Brs Reddy.
Anyone explain the answer for this question.
Anyone explain the answer for this question.
BRS REDDY said:
7 years ago
How many hens are there?
Soniya guchait said:
7 years ago
Awesome explanation. Thanks all.
Sourabh The great mathematician said:
8 years ago
Awesome explanation. Thanks.
Aryan said:
9 years ago
@Monica explained the right thing.
Rajat said:
9 years ago
@Monica.
As we know, the no of legs of a cow is 4 while the hen is of 2.
The number of cows was taken to be x and that of a hen be y.
Naturally, legs x heads = 4x (cow).
Legs x head = 2y (hen).
As we know, the no of legs of a cow is 4 while the hen is of 2.
The number of cows was taken to be x and that of a hen be y.
Naturally, legs x heads = 4x (cow).
Legs x head = 2y (hen).
Monica said:
9 years ago
How 4x + 2y came?
(1)
Tejaswini said:
10 years ago
Can you explain me how to solve a two different variable equation? Please as soon as possible.
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