Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 17)
17.
There are deer and peacocks in a zoo. By counting heads they are 80. The number of their legs is 200. How many peacocks are there ?
Answer: Option
Explanation:
Let x and y be the number of deer and peacocks in the zoo respectively. Then,
x + y = 80 ...(i) and
4x + 2y = 200 or 2x + y = 100 ...(ii)
Solving (i) and (ii), we get) x = 20, y = 60.
Discussion:
13 comments Page 2 of 2.
Rahul said:
8 years ago
X+y = 80.
4x+2y = 200.
Then multiple with 4.
4x+4y = 320,
4x+2y = 200,
2y = 120,
Y = 60.
4x+2y = 200.
Then multiple with 4.
4x+4y = 320,
4x+2y = 200,
2y = 120,
Y = 60.
Raju said:
1 decade ago
Can anyone tell me how to solve above question through allegation method?
Arup Das said:
3 years ago
L/2 - H.
= 200/2 - 80.
= 100 - 80,
= 20.
= 200/2 - 80.
= 100 - 80,
= 20.
(1)
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