Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 17)
17.
There are deer and peacocks in a zoo. By counting heads they are 80. The number of their legs is 200. How many peacocks are there ?
Answer: Option
Explanation:
Let x and y be the number of deer and peacocks in the zoo respectively. Then,
x + y = 80 ...(i) and
4x + 2y = 200 or 2x + y = 100 ...(ii)
Solving (i) and (ii), we get) x = 20, y = 60.
Discussion:
13 comments Page 2 of 2.
Venkat said:
8 years ago
Here total heads =80, legs=200, 60*2=120, 20*4=80, 120+80=200 legs, here 20=deers, 60=peacocks.
Shreyas Singh said:
5 years ago
Heads = 80(total heads)÷2(no. Of animals) = 40,
Legs = 200(total legs)÷2(no.of animals) = 100.
Now, 100 - 40 = 60 peacocks. Becoz total head was 80 n it's logics that less heads more legs n more heads less legs. For this type of questions;
Another way only ÷legs i.e. 200÷2=100 now 100-80( total heads).
= 20 again concept and logic are the same above mentioned. Less leg more heads less heads more legs.
Legs = 200(total legs)÷2(no.of animals) = 100.
Now, 100 - 40 = 60 peacocks. Becoz total head was 80 n it's logics that less heads more legs n more heads less legs. For this type of questions;
Another way only ÷legs i.e. 200÷2=100 now 100-80( total heads).
= 20 again concept and logic are the same above mentioned. Less leg more heads less heads more legs.
Arup Das said:
3 years ago
L/2 - H.
= 200/2 - 80.
= 100 - 80,
= 20.
= 200/2 - 80.
= 100 - 80,
= 20.
(1)
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