Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 28)
28.
A, B, C, D and E play a game of cards. A says to B, "If you give me 3 cards, you will have as many as I have at this moment while if D takes 5 cards from you, he will have as many as E has." A and C together have twice as many cards as E has. B and D together also have the same number of cards as A and C taken together. If together they have 150 cards, how many cards has C got ?
Answer: Option
Explanation:
Clearly, we have :
A = B - 3 ...(i)
D + 5 = E ...(ii)
A+C = 2E ...(iii)
B + D = A+C = 2E ...(iv)
A+B + C + D + E=150 ...(v)
From (iii), (iv) and (v), we get: 5E = 150 or E = 30.
Putting E = 30 in (ii), we get: D = 25.
Putting E = 30 and D = 25 in (iv), we get: B = 35.
Putting B = 35 in (i), we get: A = 32.
Putting A = 32 and E = 30 in (iii), we get: C = 28.
Discussion:
6 comments Page 1 of 1.
Ram said:
5 months ago
Let's denote the number of cards each player has as follows:
- ( A ) has ( a ) cards
- ( B ) has ( b ) cards
- ( C ) has ( c ) cards
- ( D ) has ( d ) cards
- ( E ) has ( e ) cards
From the problem, we can derive the following equations based on the statements made:
1. From A's statement to B:
If B gives A 3 cards, then B will have ( b - 3 ) cards and A will have ( a + 3 ) cards. The equation becomes:
b - 3 = a + 3
and b = a + 6 =>Equation 1.
2. From A's statement about D:
- If D takes 5 cards from B, then D will have ( d + 5 ) cards and B will have ( b - 5 ) cards.
The equation becomes:
d + 5 = e
And d = e - 5 =>Equation 2.
3. From A and C together have twice as many cards as E:
a + c = 2e => Equation 3.
4. From B and D together have the same number of cards as A and C:
b + d = a + c => Equation 4.
5. Total number of cards:
a + b + c + d + e = 150 => Equation 5.
Step 1: Substitute Equations
Now, we will substitute Equations 1 and 2 into the other equations.
From Equation 1:
b = a + 6
And From Equation 2:
d = e - 5
Step 2: Substitute into Equation 4:
Substituting ( b ) and ( d ) into Equation 4:
(a + 6) + (e - 5) = a + c.
This simplifies to:
a + 6 + e - 5 = a + c
=> e + 1 = c
And c = e + 1 => Equation 6.
Step 3: Substitute into Equation 3
Now substitute ( c ) from Equation 6 into Equation 3:
a + (e + 1) = 2e
This simplifies to:
a + e + 1 = 2e
a + 1 = e
And e = a + 1 => Equation 7
Step 4: Substitute into Equation 5
Now substitute ( b ), ( d ), and ( e ) into Equation 5:
a + (a + 6) + (e + 1) + (e - 5) + e = 150
Substituting ( e = a + 1 ) into the equation:
a + (a + 6) + ((a + 1) + 1) + ((a + 1) - 5) + (a + 1) = 150
This simplifies to:
a + (a + 6) + (a + 2) + (a - 4) + (a + 1) = 150.
Combining like terms:
5a + 6 + 2 - 4 + 1 = 150,
=> 5a + 5 = 150.
Thus:
5a = 145
=> a = 29.
Step 5: Find ( e ) and ( c )
Now, using Equation 7 to find ( e ):
e = a + 1 = 29 + 1 = 30
Using Equation 6 to find (c ):
c = e + 1 = 30 + 1 = 31
Conclusion:
Thus, the number of cards that C has is 31.
- ( A ) has ( a ) cards
- ( B ) has ( b ) cards
- ( C ) has ( c ) cards
- ( D ) has ( d ) cards
- ( E ) has ( e ) cards
From the problem, we can derive the following equations based on the statements made:
1. From A's statement to B:
If B gives A 3 cards, then B will have ( b - 3 ) cards and A will have ( a + 3 ) cards. The equation becomes:
b - 3 = a + 3
and b = a + 6 =>Equation 1.
2. From A's statement about D:
- If D takes 5 cards from B, then D will have ( d + 5 ) cards and B will have ( b - 5 ) cards.
The equation becomes:
d + 5 = e
And d = e - 5 =>Equation 2.
3. From A and C together have twice as many cards as E:
a + c = 2e => Equation 3.
4. From B and D together have the same number of cards as A and C:
b + d = a + c => Equation 4.
5. Total number of cards:
a + b + c + d + e = 150 => Equation 5.
Step 1: Substitute Equations
Now, we will substitute Equations 1 and 2 into the other equations.
From Equation 1:
b = a + 6
And From Equation 2:
d = e - 5
Step 2: Substitute into Equation 4:
Substituting ( b ) and ( d ) into Equation 4:
(a + 6) + (e - 5) = a + c.
This simplifies to:
a + 6 + e - 5 = a + c
=> e + 1 = c
And c = e + 1 => Equation 6.
Step 3: Substitute into Equation 3
Now substitute ( c ) from Equation 6 into Equation 3:
a + (e + 1) = 2e
This simplifies to:
a + e + 1 = 2e
a + 1 = e
And e = a + 1 => Equation 7
Step 4: Substitute into Equation 5
Now substitute ( b ), ( d ), and ( e ) into Equation 5:
a + (a + 6) + (e + 1) + (e - 5) + e = 150
Substituting ( e = a + 1 ) into the equation:
a + (a + 6) + ((a + 1) + 1) + ((a + 1) - 5) + (a + 1) = 150
This simplifies to:
a + (a + 6) + (a + 2) + (a - 4) + (a + 1) = 150.
Combining like terms:
5a + 6 + 2 - 4 + 1 = 150,
=> 5a + 5 = 150.
Thus:
5a = 145
=> a = 29.
Step 5: Find ( e ) and ( c )
Now, using Equation 7 to find ( e ):
e = a + 1 = 29 + 1 = 30
Using Equation 6 to find (c ):
c = e + 1 = 30 + 1 = 31
Conclusion:
Thus, the number of cards that C has is 31.
Aravind said:
5 years ago
A + 3 = B - 3 is the first condition; since A asks B to give 3 cards so that they have equal number of cards.
Therefore, the answer is C has 31 cards.
Therefore, the answer is C has 31 cards.
Pooja said:
7 years ago
A ask the B to give 3 card. So, that B will have as much as A in this moment. That means A is not received 3 card in this moment.
That is, answer is 28.
That is, answer is 28.
HARISH said:
9 years ago
I think the answer is incorrect.
In the first, it should be A + 3 = B - 3 but not A = B - 3 then answer becomes C = 31 NOT 28 because he asked at this momment when B is giving three cards to A then B have B - 3 and A have A + 3 and said it is equal.
In the first, it should be A + 3 = B - 3 but not A = B - 3 then answer becomes C = 31 NOT 28 because he asked at this momment when B is giving three cards to A then B have B - 3 and A have A + 3 and said it is equal.
Pritham said:
1 decade ago
Putting E = 30 and D = 25 in (iv), we get:B = 35. How 35 comes?
Saurabh said:
1 decade ago
How this D+5 = E came?
What I think is - B gave his five cards to D therefore D = B+5;
What I think is - B gave his five cards to D therefore D = B+5;
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