Verbal Reasoning - Arithmetic Reasoning - Discussion

Discussion :: Arithmetic Reasoning - Section 1 (Q.No.45)

45. 

In a cricket match, five batsmen A, B, C, D and E scored an average of 36 runs. D Scored 5 more than E; E scored 8 fewer than A; B scored as many as D and E combined; and B and C scored 107 between them. How many runs did E score ?

[A]. 62
[B]. 45
[C]. 28
[D]. 20

Answer: Option D

Explanation:

Total runs scored = (36 x 5) = 180.

Let the runs scored by E be x.

Then, runs scored by D = x + 5; runs scored by A = x + 8;

runs scored by B = x + x + 5 = 2x + 5;

runs scored by C = (107 - B) = 107 - (2x + 5) = 102 - 2x.

So, total runs = (x + 8) + (2x + 5) + (102 - 2x) + (x + 5) + x = 3x + 120.

Therefore 3x + 120 =180 3X = 60 x = 20.


Azharuddin said: (Jun 14, 2013)  
Simply you can do it like this:

(E+8)+107+(E+5)+E = 180.

3E+120 = 180.

E = 20.

Wakabala Elly said: (Feb 16, 2017)  
@Azharuddin.

Your solution is so short and clear. I have got it now. Thanks.

Siyad said: (Jun 15, 2017)  
@Azharuddin.

Well said, Thanks @Azharuddin.

Debishree said: (Sep 20, 2017)  
@Azharuddin.

Its easy and clear. Thanks.

Angle said: (Oct 30, 2017)  
How can I get 180?

Deep said: (May 11, 2018)  
How can I get 180? Please explain.

Kootu Richard said: (Sep 2, 2018)  
How come 180 here?

Sunita said: (Sep 12, 2018)  
How come 180? Explain.

Shivish said: (Oct 7, 2018)  
(A+B+C+D+E)/5 = 36.
36*5 = 180.

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