Verbal Reasoning - Arithmetic Reasoning - Discussion

Discussion Forum : Arithmetic Reasoning - Section 2 (Q.No. 16)
16.
A player holds 13 cards of four suits, of which seven are black and six are red. There are twice as many diamonds as spades and twice as many hearts as diamonds. How many clubs does he hold ?
4
5
6
7
Answer: Option
Explanation:

Clearly, the black cards are either clubs or spades while the red cards are either diamonds or hearts.

Let the number of spades be x. Then, number of clubs = (7 - x).

Number of diamonds = 2 x number of spades = 2x;

Number of hearts = 2 x number of diamonds = 4x.

Total number of cards = x + 2x + 4x + 7 - x = 6x + 7.

Therefore 6x + 7 = 13 6x = 6 x - 1.

Hence, number of clubs = (7 - x) = 6.

Discussion:
3 comments Page 1 of 1.

Anmol said:   2 years ago
Red= 6 (Diamonds and Hearts)
Black= 7 ( Clubs and spades)
According to question: There are twice as many hearts as diamonds means; Heart = 4 and diamonds = 2 (Total must be 6 because both are red) Then twice as many diamonds as spades means Diamonds = 2 therefore Spades = 1.
Now Clubs = Total black - Spades (7-1) = 6 Ans.
(2)

Ashy said:   8 years ago
Consider no.of spades as "X"
Only spades and clubs are black.
There are 7 black cards.
So no.of clubs = 7-x.

From the given data,
Diamonds = 2*spades (x) = 2x.
Heart = 2*diamonds(2x) = 4x.

Total red cards = 6.

Therefore, 6x = 6.
And x = 1.
Therefore club = 7-x=7-1=6 (Ans).

Namrata said:   1 decade ago
Can some one explain me answer in simple way?

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