Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 2 (Q.No. 20)
20.
After distributing the sweets equally among 25 children, 8 sweets remain. Had the number of children been 28, 22 sweets would have been left after equal distribution. What was the total number of sweets ?
Answer: Option
Explanation:
Let the total number of sweets be (25x + 8).
Then, (25x + 8) - 22 is divisible by 28
(25x - 14) is divisible by 28 28x - (3x + 14) is divisible by 28
(3x + 14) is divisible by 28 x = 14.
Therefore Total number of sweets = (25 x 14 + 8) = 358.
Discussion:
12 comments Page 2 of 2.
Raj Kapoor said:
3 years ago
@Jansher Baloch.
But the number of sweets distributed equally both times is same or not is didn't specify here, right?
But the number of sweets distributed equally both times is same or not is didn't specify here, right?
Ayan Banerjee said:
2 years ago
Let us assume the total number of sweets are x.
When it is divided among 25 children=x/25 giving the remainder 8 And when it is divided among 28 children=x/28 giving the remainder 22.
Taking options;
A. 328/25 gives the remainder 3.
B. 348/25 gives the remainder 23.
C. 358/25 gives the remainder 8 and 358/28 gives the remainder 22.
Hence the correct option is C. 358.
When it is divided among 25 children=x/25 giving the remainder 8 And when it is divided among 28 children=x/28 giving the remainder 22.
Taking options;
A. 328/25 gives the remainder 3.
B. 348/25 gives the remainder 23.
C. 358/25 gives the remainder 8 and 358/28 gives the remainder 22.
Hence the correct option is C. 358.
(4)
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