Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 2 (Q.No. 20)
20.
After distributing the sweets equally among 25 children, 8 sweets remain. Had the number of children been 28, 22 sweets would have been left after equal distribution. What was the total number of sweets ?
Answer: Option
Explanation:
Let the total number of sweets be (25x + 8).
Then, (25x + 8) - 22 is divisible by 28
(25x - 14) is divisible by 28 28x - (3x + 14) is divisible by 28
(3x + 14) is divisible by 28 x = 14.
Therefore Total number of sweets = (25 x 14 + 8) = 358.
Discussion:
12 comments Page 1 of 2.
Ayan Banerjee said:
2 years ago
Let us assume the total number of sweets are x.
When it is divided among 25 children=x/25 giving the remainder 8 And when it is divided among 28 children=x/28 giving the remainder 22.
Taking options;
A. 328/25 gives the remainder 3.
B. 348/25 gives the remainder 23.
C. 358/25 gives the remainder 8 and 358/28 gives the remainder 22.
Hence the correct option is C. 358.
When it is divided among 25 children=x/25 giving the remainder 8 And when it is divided among 28 children=x/28 giving the remainder 22.
Taking options;
A. 328/25 gives the remainder 3.
B. 348/25 gives the remainder 23.
C. 358/25 gives the remainder 8 and 358/28 gives the remainder 22.
Hence the correct option is C. 358.
(4)
Jansher Baloch said:
7 years ago
Let X number of the sweet distributing each student. Therefore, a total number of sweets is 25X + 8 when it distributing among 25 children and 28X - 22 when it distributing among 28 children.
Therefore, 28X - 22 = 25X + 8.
=> 28X - 25X = 8 + 22,
=> 3X = 30,
=> X = 10,
Therefore total number of sweets is 25x10 + 8 = 258.
Therefore, 28X - 22 = 25X + 8.
=> 28X - 25X = 8 + 22,
=> 3X = 30,
=> X = 10,
Therefore total number of sweets is 25x10 + 8 = 258.
Santhosh said:
1 decade ago
Yes you are right @Abhi.
Sweets=8+25*(each).......(1).
Sweets=22+28*(each)....(2).
Subtracting above we get,
3x+14 when x=14 it is divisible by 28.
So substitute x=14 in Total number of sweets = (25 x 14 + 8) = 358.
Sweets=8+25*(each).......(1).
Sweets=22+28*(each)....(2).
Subtracting above we get,
3x+14 when x=14 it is divisible by 28.
So substitute x=14 in Total number of sweets = (25 x 14 + 8) = 358.
Shanmugam said:
6 years ago
Check every option... etc
Option A : 328.
328/25 = 13 and 3 so not correct (Also do 328/28)
Option B : 348.
348/25 =13 and 23 not correct
Option C : 358.
358/25 = 14 and 8 its correct
358/28 =12 and 22.
Option A : 328.
328/25 = 13 and 3 so not correct (Also do 328/28)
Option B : 348.
348/25 =13 and 23 not correct
Option C : 358.
358/25 = 14 and 8 its correct
358/28 =12 and 22.
(4)
Raj Kapoor said:
3 years ago
@Jansher Baloch.
But the number of sweets distributed equally both times is same or not is didn't specify here, right?
But the number of sweets distributed equally both times is same or not is didn't specify here, right?
Abhi said:
1 decade ago
sweets=8+25*(each).......(1)
sweets=22+28*(each)....(2)
by solving we get each and sweets.
is this way not correct?
sweets=22+28*(each)....(2)
by solving we get each and sweets.
is this way not correct?
Anjali said:
1 decade ago
Find the no which is divisible by 25 and give reminder 8 and which is divisible by 28 and give reminder 22.
Viren shah said:
8 years ago
Can't understand.
Please, suggest any easy method.
Please, suggest any easy method.
Pmis said:
7 years ago
Please explain the solution clearly.
Sindhu said:
1 decade ago
I can't understand this problem.
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