Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 2)
2.
Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?
Answer: Option
Explanation:
Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city A.
Then, 2x + 3y = 77 ...(i) and
3x + 2y = 73 ...(ii)
Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.
Putting y = 17 in (i), we get: x = 13.
Discussion:
49 comments Page 2 of 5.
M.Haseeb Sahal Shah said:
1 decade ago
2x+3y = 77.
2x = 77 -3y.
x = 77 - 3y /2 ... (1).
3x+2y = 73.
Put x value,
3(77 - 3y /2)+ 2y = 73.
3(77 - 3y)= 2(73-2y).
231-9y = 146-4y.
231-146 = -4y+9y.
85 = 5y.
85/5 =y.
17 = y.
x = 77 - 3y /2 ... (1).
x = 77 - 3(17) /2.
x = 77 - 51 /2.
x = 26/2.
x = 13.
B is answer 13, 17.
2x = 77 -3y.
x = 77 - 3y /2 ... (1).
3x+2y = 73.
Put x value,
3(77 - 3y /2)+ 2y = 73.
3(77 - 3y)= 2(73-2y).
231-9y = 146-4y.
231-146 = -4y+9y.
85 = 5y.
85/5 =y.
17 = y.
x = 77 - 3y /2 ... (1).
x = 77 - 3(17) /2.
x = 77 - 51 /2.
x = 26/2.
x = 13.
B is answer 13, 17.
Deep said:
1 decade ago
Vijay why did you first multiply by 3 and then by 2 why not the reverse... How would you manage the negative output when you multiply first line by 2 and second line by 3
i.e 4x + 6y
9x + 6x
-------------
Minus = 5x ?
Don't know if I made sense with my question.
i.e 4x + 6y
9x + 6x
-------------
Minus = 5x ?
Don't know if I made sense with my question.
Ramkumar said:
1 decade ago
Its very simple.
It is a optional based solution .
There forms :
2x+3y = 77.
3x+2y = 73 (then we find x and y).
Simply check with A B C D options.
Now option B is: 13, 17 is satisfies the above equations.
It is a optional based solution .
There forms :
2x+3y = 77.
3x+2y = 73 (then we find x and y).
Simply check with A B C D options.
Now option B is: 13, 17 is satisfies the above equations.
Madhu said:
1 decade ago
@Vijay
You are method is so good. easy way to understand..in Vijay method if any x,y coefficient should made equal to the values. Because we find x,y values..thats why he multiple 3 with first equation and 2 with second equation.
You are method is so good. easy way to understand..in Vijay method if any x,y coefficient should made equal to the values. Because we find x,y values..thats why he multiple 3 with first equation and 2 with second equation.
Reghu R said:
1 decade ago
2x+3y = 77 --------- i.
3x+2y = 73 --------- ii.
---------
i*2 => 4x+6y = 154.
ii*3 => 9x+6y = 219.
5x=65; x=65/5; x=13; 26+3y=77; 3y=77-26; 3y=51; y=17.
Answer = Rs.13 and Rs.17.
3x+2y = 73 --------- ii.
---------
i*2 => 4x+6y = 154.
ii*3 => 9x+6y = 219.
5x=65; x=65/5; x=13; 26+3y=77; 3y=77-26; 3y=51; y=17.
Answer = Rs.13 and Rs.17.
Chandini said:
8 years ago
2A+3B=77.....(1)
3A+2B=73.....(2)
FROM 1&2 we get A=30-B
put A value in 1 then we get 2(30-B)+3B=77.
Finally, we get B=17.
put B value either1 or 2 eqn,
we A=13
final answer 13, 17.
3A+2B=73.....(2)
FROM 1&2 we get A=30-B
put A value in 1 then we get 2(30-B)+3B=77.
Finally, we get B=17.
put B value either1 or 2 eqn,
we A=13
final answer 13, 17.
(3)
SHINDIYA said:
2 years ago
2x+3y=77 ---> (1)×3.
3x+2y=73 ---> (2)×2.
Then we get;
6x+9y = 231.
6x+4y = 146.
Ans: 5y=85 y=17,
Sub to y to 2 and equation then we get;
X=13.
3x+2y=73 ---> (2)×2.
Then we get;
6x+9y = 231.
6x+4y = 146.
Ans: 5y=85 y=17,
Sub to y to 2 and equation then we get;
X=13.
(14)
Antony said:
1 decade ago
New method
3 tickets A to B
2 tickets A to c
that's 77/5 = 15.4
3 tickets A to B
2 tickets A to C
that's 73/5 = 14.6
so 15.4+14.6 = 30
Ans: 13 + 17 = 30 --- (B)
3 tickets A to B
2 tickets A to c
that's 77/5 = 15.4
3 tickets A to B
2 tickets A to C
that's 73/5 = 14.6
so 15.4+14.6 = 30
Ans: 13 + 17 = 30 --- (B)
Rashed said:
9 years ago
Hi, I'm not much good in maths but can anybody tell me how we are multiplying these equations with 3 and 2? Where these 3 and 2 comes from?
Aneri Desai said:
1 decade ago
s2b(2) & s2a(3) = 77.
s2b(3) & s2a(2) = 73.
s2b=x=? & s2a=y=?
4x+6y = 154.
9x+6y = 219.
-5x = -65.
x = 13.
y = 17.
s2b(3) & s2a(2) = 73.
s2b=x=? & s2a=y=?
4x+6y = 154.
9x+6y = 219.
-5x = -65.
x = 13.
y = 17.
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