Verbal Reasoning - Arithmetic Reasoning - Discussion

2A+3B=77.....(1)
3A+2B=73.....(2)
FROM 1&2 we get A=30-B
put A value in 1 then we get 2(30-B)+3B=77.
Finally, we get B=17.
put B value either1 or 2 eqn,
we A=13
final answer 13, 17.

2x+3y=77-->(1)
3x+2y=73-->(2)

73(2x+3y)=77(3x+2y),
146x+219y=231x+154y,
65y=85x,
13y=17x.

@Kamaho

We have to make either x or y value 0 to get one's value.

So multiplying (i) with 3 and (ii) with 2 we will get x part 0 by equating both equations [ (i) - (ii) ] then only we get 5y=85 further values.

Also, we can multiply (i) with 2 and (ii) with 3.
Then by equating both, we will get 5x=65 then x=65/5..... x=13.

The purpose of multiplying the equations is to make either x or y equal, then by equating we will get either x or y =0.
You can take any no. For multiply, but make values of both x or both y equal.

Hope you will understand.

How to get 85?

Not understanding it.

How 3 and 2 is there?

Why do we multiply with 3&2 why not 2&3? everyone know 13&17 is the correct answer. But how & where do we get that 3 & 2 why not 2&3 anyone who can explain this for me? Yes, we know if we multiply by 3 & 2 we get an answer but how do we got that?

Let Rs. x be the cost of city B from city A and Rs. x + 4 be the cost of city C from city A.

Then, 2x + 3x + 12= 77= 5x + 12.

Which means that, 77 - 12= 65= 5x.

Thus, x= 65 ÷ 5= 13.

Because A to B is Rs. x, that means that it costs, Rs. 13 and,
Because A to C is Rs. x + 4, that menas that is costs Rs. 13 + 4, which is equal to 17.

Your solution is awesome. I got it easily through your process, Thanks @Satwant.

How to take the equation?

Why not option D?

2X + 3Y = 77 ------> 1
3X + 2Y = 73 ------> 2

1.multiply with 3.
2.multiply with 2.

6X + 9Y = 231 ------> 3
6X + 6Y = 146 ------> 4

Subtract 3 & 4.

6X + 9Y = 231
6X + 6Y = 146
-----------------------
0 + 5y = 85
y = 85/5
y = 17.

Put y value in 1 or 2.

2X + 3(17) = 77,
2X + 51 = 77,
2X = 77 - 51 = 26.
X = 26/2 = 13.
X = 13 and Y = 17.