Verbal Reasoning - Arithmetic Reasoning - Discussion

Discussion :: Arithmetic Reasoning - Section 1 (Q.No.27)

27. 

A bus starts from city X. The number of women in the bus is half of the number of men. In city Y, 10 men leave the bus and five women enter. Now, number of men and women is equal. In the beginning, how many passengers entered the bus ?

[A]. 15
[B]. 30
[C]. 36
[D]. 45

Answer: Option D

Explanation:

Originally, let number of women = x. Then, number of men = 2x.

So, in city Y, we have : (2x - 10) = (x + 5) or x - 15.

Therefore Total number of passengers in the beginning = (x + 2x) = 3x = 45.


Kan Wine said: (Nov 27, 2012)  
Let the no.of men = x
So no.of women = x/2
In city y..... (x-10)=(x/2+5)
(2x-20)=(x+10)
x=30.

Because the no.of women were half the no of men therefore total no.of passengers in the beginning = 30+15
45

Jasdeep Kaur Attwal said: (Sep 21, 2014)  
Let the no. of men in city X = A.
No. of women in city X = A/2.

When bus reached at city Y.
No of men = A-10......equ(1).

And no of women = A/2+5...equ(2).
Comparing (1) and (2).

A-10 = A/2 = 5.
A-10 = A+10/2(L.C.M OF A/2+5).
2A-20 = A+10.
2A-A = 10+20.
A = 30.

So the no.of men at city X = 30.
No.of womens = A/2 = 30/2 = 15.
In the beginning total no.of passengers entered in the bus = 30 +15 = 45.

Ariya said: (May 29, 2017)  
Total number of pax-50.
No.of women-25,
No.of men-25,
So, 50-10 = 40,
40+5 = 45.

Lakshminarasimha said: (Jul 23, 2018)  
@All.

Men + Women = 25+25.
by leaving m=10 entered w=5.
m+w= 50-10+5=45.

Mallesh G said: (Nov 8, 2018)  
Let X be women and y be men.

In city X,
x=1/2y----------> Eq 1.

In city Y.
y-10=x+5----------> Eq 2.

Solving 1 and 2
We get x=15 y=30, summing up 45 is the total count.

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