### Discussion :: Arithmetic Reasoning - Section 1 (Q.No.27)

Kan Wine said: (Nov 27, 2012) | |

Let the no.of men = x So no.of women = x/2 In city y..... (x-10)=(x/2+5) (2x-20)=(x+10) x=30. Because the no.of women were half the no of men therefore total no.of passengers in the beginning = 30+15 45 |

Jasdeep Kaur Attwal said: (Sep 21, 2014) | |

Let the no. of men in city X = A. No. of women in city X = A/2. When bus reached at city Y. No of men = A-10......equ(1). And no of women = A/2+5...equ(2). Comparing (1) and (2). A-10 = A/2 = 5. A-10 = A+10/2(L.C.M OF A/2+5). 2A-20 = A+10. 2A-A = 10+20. A = 30. So the no.of men at city X = 30. No.of womens = A/2 = 30/2 = 15. In the beginning total no.of passengers entered in the bus = 30 +15 = 45. |

Ariya said: (May 29, 2017) | |

Total number of pax-50. No.of women-25, No.of men-25, So, 50-10 = 40, 40+5 = 45. |

Lakshminarasimha said: (Jul 23, 2018) | |

@All. Men + Women = 25+25. by leaving m=10 entered w=5. m+w= 50-10+5=45. |

Mallesh G said: (Nov 8, 2018) | |

Let X be women and y be men. In city X, x=1/2y----------> Eq 1. In city Y. y-10=x+5----------> Eq 2. Solving 1 and 2 We get x=15 y=30, summing up 45 is the total count. |

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