Verbal Reasoning - Arithmetic Reasoning - Discussion

Lets say total number of students = 180 --> Multiplication of all denominators(5,9,4) - Easy for calculation.

Number of girls = (3/5)(180) = 108.
Number of boys = 180-108 = 72.
Number of girls absent = (2/9)108 = 24.
Number of boys absent = (1/4)72 = 18.
Total number of students absent = Total girls absent + Total boys absent = 24+18 = 42.
Total number of students present = Total Students - Total students absent = 180-42 = 138.
Percent of students present = 138/180 = 23/30.

@Tim :

It is as simple as (1-2/5) i.e 3/5 of the boys are present because 2/5 are absent.

Explanation: Let a total number of students X.
Now the number of boys will be (1/3)X.
And the number of boys that are absent will be 2/5 * (1/3)X = (2/15)X.
So, the number of boys present in the class will be (1/3)X - (2/15)X = (3/15)X or (1/5)X.
Hence, the required fraction = (1/5)X / (1/3)X or 3/5.

In a class 1/3 are boys. If 2/5 of the boys are absent, what fraction of the boys are present?

Help me with these, please.

Not getting the solution. Anyone explain this clearly.

Thanks for explaining the answer. Useful question.