Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 13)
13.
In a garden, there are 10 rows and 12 columns of mango trees. The distance between the two trees is 2 metres and a distance of one metre is left from all sides of the boundary of the garden. The length of the garden is
Answer: Option
Explanation:
Each row contains 12 plants.
There are 11 gapes between the two corner trees (11 x 2) metres and 1 metre on each side is left.
Therefore Length = (22 + 2) m = 24 m.
Discussion:
17 comments Page 2 of 2.
Imran Ali said:
1 decade ago
How we calculate height in the same Q some one tell me?
Udaya said:
1 decade ago
We can't calculate the height because here it is given only no.of tree.
Imran Ali said:
1 decade ago
In Q if height is asked then how it should be solve, please someone tell me?
Cyrus said:
1 decade ago
Distance can also be measured considering there are 12 trees in 1 row, each having 1 meter on either side of each tree i.e. 2 meters/tree.
Therefore: 12 trees*2 meters=24 meters length.
Therefore: 12 trees*2 meters=24 meters length.
Subbarao said:
1 decade ago
Distance between boundary and first tree=1 meter.
And there are 12 trees so distance between 12 trees =11*2=22 meters.
(distance between two trees is 2 meters).
Distance between boundary and last tree=1 meter.
1+22+1=24 meters.
And there are 12 trees so distance between 12 trees =11*2=22 meters.
(distance between two trees is 2 meters).
Distance between boundary and last tree=1 meter.
1+22+1=24 meters.
Chaman said:
1 decade ago
Answer would be 24m. Because one meter is left from all sides but its length is asked in question. So 22+ (1m from left+1m from right) =24m.
Ved Prakash said:
1 decade ago
I also think answer should be 26.
Because one metre is left from all sides of the boundary of the garden.
Because one metre is left from all sides of the boundary of the garden.
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