Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 2 (Q.No. 30)
30.
A printer numbers the pages of a book starting with 1 and uses 3189 digits in all. How many pages does the book have ?
Answer: Option
Explanation:
No. of digits in 1-digit page nos. = 1x9 = 9.
No. of digits in 2-digit page nos. = 2 x 90 = 180.
No. of digits in 3-digit page nos. = 3 x 900 = 2700.
No. of digits in 4-digit page nos. = 3189 - (9 + 180 + 2700) = 3189 - 2889 = 300.
Therefore No. of pages with 4-digit page nos. = (300/4) = 75.
Hence, total number of pages = (999 + 75) = 1074.
Discussion:
16 comments Page 2 of 2.
Najmi said:
9 years ago
If there is 2736 digits used in all then what is the number of pages?
Sam_91 said:
9 years ago
I did not understand from this step.
Number of digits in 4-digit page nos.
Why don't we calculate 4 digits from 1000 to 3189?
Number of digits in 4-digit page nos.
Why don't we calculate 4 digits from 1000 to 3189?
Zarith said:
8 years ago
Why do we divide 300 by 4? I don't understand. Please explain it.
Payal said:
7 years ago
Why do we divide 300 by 4? Please explain.
Basant bhatt said:
4 years ago
Why do we divide 300 by 4? I don't understand. Please explain.
Dileep kumar said:
3 years ago
@Najmi.
Here is the answer.
1 to 9 = 9.
10 to 99 = 90.
The remaining 2736-(180+9) = 2547 (all these digits as printed as 3 digit numbers).
100 to x = 2547/3 = 849.
total pages = 9 +90 + 849 = 948 pages.
Here is the answer.
1 to 9 = 9.
10 to 99 = 90.
The remaining 2736-(180+9) = 2547 (all these digits as printed as 3 digit numbers).
100 to x = 2547/3 = 849.
total pages = 9 +90 + 849 = 948 pages.
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