Verbal Reasoning - Arithmetic Reasoning - Discussion

Discussion Forum : Arithmetic Reasoning - Section 2 (Q.No. 30)
30.
A printer numbers the pages of a book starting with 1 and uses 3189 digits in all. How many pages does the book have ?
1000
1074
1075
1080
Answer: Option
Explanation:

No. of digits in 1-digit page nos. = 1x9 = 9.

No. of digits in 2-digit page nos. = 2 x 90 = 180.

No. of digits in 3-digit page nos. = 3 x 900 = 2700.

No. of digits in 4-digit page nos. = 3189 - (9 + 180 + 2700) = 3189 - 2889 = 300.

Therefore No. of pages with 4-digit page nos. = (300/4) = 75.

Hence, total number of pages = (999 + 75) = 1074.

Discussion:
16 comments Page 2 of 2.

Dev Yadav said:   10 years ago
If there is 1242 digits used in all then.

Akash said:   10 years ago
9 digits covered in 1-9 pg no.

90*2 = 180 digits covered in 10-99 pg no.

900*3 = 2700 digits covered in 100-999 pg no.

Now 3189-(9+180+2700) = 300 digits will cover in 4 digits pg no.

So 300/4 pages will take to cover 300 nos.

i.e 75. Now total pages will be 999+75 = 1074 pages.

Souvik said:   1 decade ago
No of pages with 1-digit page no=9/1 = 9.

No of pages with 2-digit page no=180/2 = 90.

No of pages with 3-digit page no=2700/3 = 900.

Total no of pages with 1-digit, 2-digit and 3-digit numbers = 9+90+900 = 999.

Required no of pages = 999+75 = 1074.

Chandu said:   1 decade ago
Where from 999 came?

Rahul Verma said:   1 decade ago
@Sowmya.

Because from 10 -99 there are 90 pages with two digits.

Sowmya said:   1 decade ago
I did not understand the procedure from 2nd step. Why did he take 90 in 2nd step?


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