Verbal Reasoning - Arithmetic Reasoning - Discussion

Discussion :: Arithmetic Reasoning - Section 1 (Q.No.12)

12. 

The 30 members of a club decided to play a badminton singles tournament. Every time a member loses a game he is out of the tournament. There are no ties. What is the minimum number of matches that must be played to determine the winner ?

[A]. 15
[B]. 29
[C]. 61
[D]. None of these

Answer: Option B

Explanation:

Clearly, every member except one (i.e. the winner) must lose one game to decide the winner. Thus, minimum number of matches to be played = 30 - 1 = 29.


Ananta said: (Nov 20, 2012)  
Is their any altranative method sir ?

Jebas said: (Dec 1, 2012)  
Game can be divided into 4 sets.

1st set:
30 members can be alloted 15 games with 2 members each = 15 winners(15 matches)

2nd set:
15 winners can be separated into 14 + 1 members.
7 matches can be alloted for 14 members = 7 winners(7 matches) with 1 member remaining.

3rd set:
7 winners can be separated into 6 + 1 members.
3 matches can be alloted for first six members = 3 winners(3 matches).
1 match can be alloted for 2nd and 3rd set left out peoples = 1 winner(1 match). Totally 4 matches in 3rd set

4th set:
Now we have 4 winners from which 2 semi final match and 1 final match can be played(3 matches) to decide the winner.

Total matches played from 4 sets: 15+7+4+3 = 29.

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