Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 12)
12.
The 30 members of a club decided to play a badminton singles tournament. Every time a member loses a game he is out of the tournament. There are no ties. What is the minimum number of matches that must be played to determine the winner ?
Answer: Option
Explanation:
Clearly, every member except one (i.e. the winner) must lose one game to decide the winner. Thus, minimum number of matches to be played = 30 - 1 = 29.
Discussion:
3 comments Page 1 of 1.
HLG SAGAR said:
1 year ago
For 30 people, 15 matches are played, so, 15 members are left now.
For 15 people, 7 matches are played, 1 left[lucky draw], so now 7+1 =8 people left.
For 8 people, 4 matches were played, so left with 4 people.
For 4 people, 2 matches played, 2 people left.
He is the winner for 2 people, 1 match played, and 1 left.
Matches = 15+7+4+2+1 = 29 matches total played.
For 15 people, 7 matches are played, 1 left[lucky draw], so now 7+1 =8 people left.
For 8 people, 4 matches were played, so left with 4 people.
For 4 people, 2 matches played, 2 people left.
He is the winner for 2 people, 1 match played, and 1 left.
Matches = 15+7+4+2+1 = 29 matches total played.
(6)
Jebas said:
1 decade ago
Game can be divided into 4 sets.
1st set:
30 members can be alloted 15 games with 2 members each = 15 winners(15 matches)
2nd set:
15 winners can be separated into 14 + 1 members.
7 matches can be alloted for 14 members = 7 winners(7 matches) with 1 member remaining.
3rd set:
7 winners can be separated into 6 + 1 members.
3 matches can be alloted for first six members = 3 winners(3 matches).
1 match can be alloted for 2nd and 3rd set left out peoples = 1 winner(1 match). Totally 4 matches in 3rd set
4th set:
Now we have 4 winners from which 2 semi final match and 1 final match can be played(3 matches) to decide the winner.
Total matches played from 4 sets: 15+7+4+3 = 29.
1st set:
30 members can be alloted 15 games with 2 members each = 15 winners(15 matches)
2nd set:
15 winners can be separated into 14 + 1 members.
7 matches can be alloted for 14 members = 7 winners(7 matches) with 1 member remaining.
3rd set:
7 winners can be separated into 6 + 1 members.
3 matches can be alloted for first six members = 3 winners(3 matches).
1 match can be alloted for 2nd and 3rd set left out peoples = 1 winner(1 match). Totally 4 matches in 3rd set
4th set:
Now we have 4 winners from which 2 semi final match and 1 final match can be played(3 matches) to decide the winner.
Total matches played from 4 sets: 15+7+4+3 = 29.
(4)
Ananta said:
1 decade ago
Is their any altranative method sir ?
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