Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 33)
33.
A bird shooter was askgd how many birds he had in the bag. He replied that there were all sparrows but six, all pigeons but six, and all ducks but six. How many birds he had in the bag in all?
Answer: Option
Explanation:
There were all sparrows but six' means that six birds were not sparrows but only pigeons and ducks.
Similarly, number of sparrows + number of ducks = 6 and number of sparrows + number of pigeons = 6.
This is possible when there are 3 sparrows, 3 pigeons and 3 ducks i.e. 9 birds in all.
Discussion:
12 comments Page 1 of 2.
Ganesh said:
2 years ago
I am not getting this. Anyone, please help me to get this in detail.
(1)
Cherry said:
5 years ago
There are 9 birds in all.
Let a total number of birds = x.
Let no of sparrows = s, pigeons = p, ducks = d.
Given s = x - 6. d = x - 6. p = x - 6.
s + d + p = x = 3x - 18.
So x = 9.
There are 9 birds in all.
Let a total number of birds = x.
Let no of sparrows = s, pigeons = p, ducks = d.
Given s = x - 6. d = x - 6. p = x - 6.
s + d + p = x = 3x - 18.
So x = 9.
There are 9 birds in all.
(4)
Swastik said:
6 years ago
This sentence "all sparrows but six" it simply means that " all sparrows but six are other birds"
So number of sparrows will be,
S = total -6;
P = total-6;
D = total-6;
S+P+D = total.
So by solving we get,
Total = 9 birds.
So number of sparrows will be,
S = total -6;
P = total-6;
D = total-6;
S+P+D = total.
So by solving we get,
Total = 9 birds.
(1)
Ranjith said:
6 years ago
I am not understanding this. Please, anyone explain this.
Ashmit Chatterjee said:
8 years ago
Let a total number of birds = x.
Let no of sparrows = s, pigeons = p, ducks = d.
Given s = x - 6. d = x - 6. p = x - 6.
s + d + p = x = 3x - 18.
So x = 9.
There are 9 birds in all.
Let a total number of birds = x.
Let no of sparrows = s, pigeons = p, ducks = d.
Given s = x - 6. d = x - 6. p = x - 6.
s + d + p = x = 3x - 18.
So x = 9.
There are 9 birds in all.
Let no of sparrows = s, pigeons = p, ducks = d.
Given s = x - 6. d = x - 6. p = x - 6.
s + d + p = x = 3x - 18.
So x = 9.
There are 9 birds in all.
Let a total number of birds = x.
Let no of sparrows = s, pigeons = p, ducks = d.
Given s = x - 6. d = x - 6. p = x - 6.
s + d + p = x = 3x - 18.
So x = 9.
There are 9 birds in all.
Ritesh Raj said:
8 years ago
Correct Answer is 9.
Ritesh Raj said:
8 years ago
Correct Answer is 9.
Batman said:
8 years ago
Hello, The correct answer is 27.
Pratyasha said:
9 years ago
Let total number of birds = x.
Let no of sparrows = s, pigeons = p, ducks = d.
Given s = x - 6. d = x - 6. p = x - 6.
s + d + p = x = 3x - 18.
So x = 9.
There are 9 birds in all.
Let no of sparrows = s, pigeons = p, ducks = d.
Given s = x - 6. d = x - 6. p = x - 6.
s + d + p = x = 3x - 18.
So x = 9.
There are 9 birds in all.
BHOOTnath said:
1 decade ago
All sparrow but 6 are not sparrows = 6 = p+d.
All sparrow but 6 are not pigeons = 6 = s+d.
All sparrow but 6 are not ducks = 6 = p+s.
So total birds are = 6+6+6 = 18.
i.e p+d+s+d+p+s = 18.
= 2(p+d+s) = 18.
P+d+s = 9.
i.e possibility of 9 in equality is 3=p, 3=d, 3=s.
All sparrow but 6 are not pigeons = 6 = s+d.
All sparrow but 6 are not ducks = 6 = p+s.
So total birds are = 6+6+6 = 18.
i.e p+d+s+d+p+s = 18.
= 2(p+d+s) = 18.
P+d+s = 9.
i.e possibility of 9 in equality is 3=p, 3=d, 3=s.
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