Online Electronics and Communication Engineering Test - Previous Exam Papers Test 6

Efficiency of antenna

Power gain = 10

Thus directivity .

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(2)₃ + (3)₄ = 2 + 3 = 5 and (10)₅ = 5¹ + 0 = 5

∴ (2)₃ + (3)₄ = (10)₅ .

X(Z) = 5.e^-0.05n.Z^-n

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Voltage across 5 Ω = 10 V

Thus voltage across 7 Ω = 10 V (5 Ω || 7 Ω)

Let the constant amplitude complex valued exponential sequence.

x(n) = Ae^-jωn

Energy = |x(n)|² = |Ae^-jωn|²

A² |(e^-jωn)|² = A²(∞) = ∞

Hence energy in infinite.

Z₁₁(s) = Z₁(s) + Z₂(s) = 1 Ω.

h(t) = s(T - t).

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Two JK flip flop. Thus propagation delay will be 2ΔT

Frequency is getting reduced by a factor e.

The signal g(t) given above is a gaussian pulse and it satisfies the relation

g(t) = - 2pt g(t)

∴ Its fourier transform is same as the signal itself in frequency domain

G(f) = e^-pf2

G(1/p) = e^-p(1/p)2 = e^-1/p.

P_i = 1 x k x s^-1 x 1 ⇒

, L₂ = k x s^-1

System will be stable when k - 3 > 0 or k > 3.