Online C Programming Test - C Programming Test - Random
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- Total number of questions: 20.
- Time allotted: 30 minutes.
- Each question carries 1 mark; there are no negative marks.
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- All the best!
Marks : 2/20
Test Review : View answers and explanation for this test.
/* Example for ceil() and floor() functions: */
#include<stdio.h>
#include<math.h>
int main()
{
printf("\n Result : %f" , ceil(1.44) );
printf("\n Result : %f" , ceil(1.66) );
printf("\n Result : %f" , floor(1.44) );
printf("\n Result : %f" , floor(1.66) );
return 0;
}
// Output:
// Result : 2.000000
// Result : 2.000000
// Result : 1.000000
// Result : 1.000000
#include<stdio.h>
int main()
{
int i=3;
switch(i)
{
case 1:
printf("Hello\n");
case 2:
printf("Hi\n");
case 3:
continue;
default:
printf("Bye\n");
}
return 0;
}
The keyword continue cannot be used in switch case. It must be used in for or while or do while loop. If there is any looping statement in switch case then we can use continue.
#include<stdio.h>
int main()
{
short int i = 0;
for(i<=5 && i>=-1; ++i; i>0)
printf("%u,", i);
return 0;
}
for(i<=5 && i>=-1; ++i; i>0) so expression i<=5 && i>=-1 initializes for loop. expression ++i is the loop condition. expression i>0 is the increment expression.
In for( i <= 5 && i >= -1; ++i; i>0) expression i<=5 && i>=-1 evaluates to one.
Loop condition always get evaluated to true. Also at this point it increases i by one.
An increment_expression i>0 has no effect on value of i.so for loop get executed till the limit of integer (ie. 65535)
#include<stdio.h>
int main()
{
int i=4;
switch(i)
{
default:
printf("This is default\n");
case 1:
printf("This is case 1\n");
break;
case 2:
printf("This is case 2\n");
break;
case 3:
printf("This is case 3\n");
}
return 0;
}
In the very begining of switch-case statement default statement is encountered. So, it prints "This is default".
In default statement there is no break; statement is included. So it prints the case 1 statements. "This is case 1".
Then the break; statement is encountered. Hence the program exits from the switch-case block.
#include<stdio.h>
int main()
{
int i = 10, j = 20;
if(i = 5) && if(j = 10)
printf("Have a nice day");
return 0;
}
"Expression syntax" error occur in this line if(i = 5) && if(j = 10).
It should be like if((i == 5) && (j == 10)).
#include<stdio.h>
int main()
{
float f=43.20;
printf("%e, ", f);
printf("%f, ", f);
printf("%g", f);
return 0;
}
printf("%e, ", f); Here '%e' specifies the "Scientific Notation" format. So, it prints the 43.20 as 4.320000e+01.
printf("%f, ", f); Here '%f' specifies the "Decimal Floating Point" format. So, it prints the 43.20 as 43.200001.
printf("%g, ", f); Here '%g' "Use the shorter of %e or %f". So, it prints the 43.20 as 43.2.
#include<stdio.h>
int main()
{
float a;
scanf("%f", &a);
printf("%f\n", a+a+a);
printf("%f\n", 3*a);
return 0;
}
#include<stdio.h>
int main()
{
printf("%p\n", main());
return 0;
}
In printf("%p\n", main()); it calls the main() function and then it repeats infinetly, untill stack overflow.
#include<stdio.h>
int main()
{
int a[3][4] = {1, 2, 3, 4, 4, 3, 2, 1, 7, 8, 9, 0};
printf("%u, %u\n", a+1, &a+1);
return 0;
}
Step 1: int a[3][4] = {1, 2, 3, 4, 4, 3, 2, 1, 7, 8, 9, 0}; The array a[3][4] is declared as an integer array having the 3 rows and 4 colums dimensions.
Step 2: printf("%u, %u\n", a+1, &a+1);
The base address(also the address of the first element) of array is 65472.
For a two-dimensional array like a reference to array has type "pointer to array of 4 ints". Therefore, a+1 is pointing to the memory location of first element of the second row in array a. Hence 65472 + (4 ints * 2 bytes) = 65480
Then, &a has type "pointer to array of 3 arrays of 4 ints", totally 12 ints. Therefore, &a+1 denotes "12 ints * 2 bytes * 1 = 24 bytes".
Hence, begining address 65472 + 24 = 65496. So, &a+1 = 65496
Hence the output of the program is 65480, 65496
Option A is the correct function to find the length of given string.
Example:
#include<stdio.h>
int xstrlen(char *s)
{
int length=0;
while(*s!='\0')
{ length++; s++; }
return (length);
}
int main()
{
char d[] = "IndiaBIX";
printf("Length = %d\n", xstrlen(d));
return 0;
}
Output: Length = 8
#include<stdio.h>
int main()
{
int i=32, j=0x20, k, l, m;
k=i|j;
l=i&j;
m=k^l;
printf("%d, %d, %d, %d, %d\n", i, j, k, l, m);
return 0;
}
#include<stdio.h>
int main()
{
int y=128;
const int x=y;
printf("%d\n", x);
return 0;
}
Step 1: int y=128; The variable 'y' is declared as an integer type and initialized to value "128".
Step 2: const int x=y; The constant variable 'x' is declared as an integer and it is initialized with the variable 'y' value.
Step 3: printf("%d\n", x); It prints the value of variable 'x'.
Hence the output of the program is "128"
int *ptr[30];#include<stdio.h>
double i;
int main()
{
(int)(float)(char) i;
printf("%d", sizeof((int)(float)(char)i));
return 0;
}
In Turbo C (DOS - 16 bit platform), the output will be 2.
But in GCC (Unix/Linux - 32 bit platform), the output will be 4.
void(*f)(int, void(*)());
char far *far *scr;
char far far** scr;
FILE - a structure containing the information about a file or text stream needed to perform input or output operations on it, including:
=> a file descriptor, the current stream position,
=> an end-of-file indicator,
=> an error indicator,
=> a pointer to the stream's buffer, if applicable
fpos_t - a non-array type capable of uniquely identifying the position of every byte in a file.
size_t - an unsigned integer type which is the type of the result of the sizeof operator.