Discussion :: Library Functions - Find Output of Program (Q.No.3)
| Ravi said: (Aug 17, 2011) | |
| How this works? | |
| Vasantha Deepika said: (Aug 27, 2012) | |
| Can any explain in detail how does it works? | |
| Akanksha Jain said: (May 9, 2013) | |
| Could you please explain how its throwing output as 2, when I ran this in gcc compiler(32 bit) which is provided here, it was throwing output as "-1"? | |
| Sachin said: (Jul 12, 2014) | |
| How this works? | |
| Maneesh Singh said: (Jul 30, 2014) | |
| scanf is also a function and it has a return type so whenever you call any scanf function in printf it gives you return value either 1 or 0. 1 means success and 0 means fail. for ex - int a=10, b= 20; printf("%d", add(a, b)); int add(int x, int y) { return (x+y); } In this ex printf will print return value of add fn that is 30..same way scanf will print its return value if success then 1 else 0... Try this: int d =0; printf("d= %d, d1 = %d, d2 = %d\n", d, scanf("%d", &d), d); |
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| Bilal said: (Sep 18, 2014) | |
| When you write scanf() it awaits for an input, why would you get get 2 as output when the input is not even entered? | |
| Arungv said: (Nov 5, 2014) | |
| #include<stdio.h> int main() { int i; i = scanf("%d %d", &i, &i); printf("%d\n", i); return 0; } Output is -1(this only i got ) in 32 Linux platform. |
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| Amit Shrivastav said: (Aug 15, 2016) | |
| The output is -1, let me correct or explain how I got output a is -1. | |
| Raman said: (Apr 14, 2018) | |
| Can anybody explain in detail? | |
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