Networking - Subnetting - Discussion

Discussion Forum : Subnetting - Subnetting (Q.No. 2)
2.
Which two statements describe the IP address 10.16.3.65/23?
  1. The subnet address is 10.16.3.0 255.255.254.0.
  2. The lowest host address in the subnet is 10.16.2.1 255.255.254.0.
  3. The last valid host address in the subnet is 10.16.2.254 255.255.254.0.
  4. The broadcast address of the subnet is 10.16.3.255 255.255.254.0.
1 and 3
2 and 4
1, 2 and 4
2, 3 and 4
Answer: Option
Explanation:
The mask 255.255.254.0 (/23) used with a Class A address means that there are 15 subnet bits and 9 host bits. The block size in the third octet is 2 (256 - 254). So this makes the subnets in the interesting octet 0, 2, 4, 6, etc., all the way to 254. The host 10.16.3.65 is in the 2.0 subnet. The next subnet is 4.0, so the broadcast address for the 2.0 subnet is 3.255. The valid host addresses are 2.1 through 3.254.
Discussion:
37 comments Page 1 of 4.

Segar said:   1 year ago
IP address converted to binary (128 64 32 16 8 4 2 1):
10.16.3.65 is 00001010-00010000-00000011-01000001

Subnet /23 is 11111111-11111111-11111110-00000000.
Network id: 00001010-00001000-00000010-00000000 (10.16.2.0).
Broadcastid: 00001010-00001000-00000011-11111111 (10.16.3.255).
Therefore host address range: 10.16.2.1 to 10.16.3.254.
(5)

Rocky said:   2 years ago
I didn't get the proper explanation.

So, please explain to me properly. (10.16.0.1 - 10.16.0.254) is this the correct range?

Chontee said:   3 years ago
How to find the subnet of any address? Please explain.

Christian luora said:   4 years ago
Why is option 1 not correct, is it true to say that a subnet address is the same as a subnet mask?


According to me, it is option 2 and 4.

Anyone, please explain in detail.
(1)

Gexun said:   5 years ago
Thank you for explaining the answer.

Thishmi said:   6 years ago
Why subnet mask can't take as 255.255.254.0 in option A?

Venkatesh said:   6 years ago
The subnet mask for the mentioned IP address is 255.255.254.0 then option 1 is also correct right.
(2)

Usama said:   6 years ago
B) is the correct answer.

The correct explanation is;

First, understand the question, Describe the IP 10.16.3.65/23
let's start from the beginning 11111111.11111111.11111110.00000000/23 which mean we are in the third octet.

How many zeroes we have in the third octet? One so 2^1=2 each network.

Now the answer will be:
First =10.16.0.0 (to) 10.16.1.255
10.16.0.0 this is N/W
10.16.0.1 first IP
10.16.1.254 last IP
10.16.1.255 Broadcast

Second= 10.16.2.0 (to) 10.16.3.255
10.16.2.0 N/W
10.16.2.1 First IP
10.16.3.254 last IP
10.16.3.255 Broadcast

And the question asking IP of 10.16.3.65 which is between the second N/W the first or lowest host in second N/W is 10.16.2.1 and last 10.16.3.254 the 255 is broadcast.

Note: 10.16.3.65/23 lock to the 23 which mean 8+8+7+0. (11111111+11111111+11111110+00000000) How many Zeros we have in the third octet? One So you need to use this formula to get the IP each N/W 2^(number of zeros) in the octet where we are.
(6)

Sourav chettr said:   6 years ago
Why option A is not correct?

Monty said:   6 years ago
Why not option A? Please explain.


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