Networking - Subnetting - Discussion
Discussion Forum : Subnetting - Subnetting (Q.No. 2)
2.
Which two statements describe the IP address 10.16.3.65/23?
- The subnet address is 10.16.3.0 255.255.254.0.
- The lowest host address in the subnet is 10.16.2.1 255.255.254.0.
- The last valid host address in the subnet is 10.16.2.254 255.255.254.0.
- The broadcast address of the subnet is 10.16.3.255 255.255.254.0.
Answer: Option
Explanation:
The mask 255.255.254.0 (/23) used with a Class A address means that there are 15 subnet bits and 9 host bits. The block size in the third octet is 2 (256 - 254). So this makes the subnets in the interesting octet 0, 2, 4, 6, etc., all the way to 254. The host 10.16.3.65 is in the 2.0 subnet. The next subnet is 4.0, so the broadcast address for the 2.0 subnet is 3.255. The valid host addresses are 2.1 through 3.254.
Discussion:
37 comments Page 2 of 4.
Shailendra kumar yadav said:
8 years ago
The lowest host address in the subnet is 10.16.2.1 255.255.254.0.
It is incorrect because the lowest host address in the subnet is 10.16.3.254 255.255.254.0.
It is incorrect because the lowest host address in the subnet is 10.16.3.254 255.255.254.0.
Nia said:
8 years ago
I think first address should be 10.16.2.0 instead of 10.16.2.1.
because 2^(32-23) = 2^9,
3 : 0 0 0 0 0 0 1 1,
65 : 0 1 0 0 0 0 0 1.
9 means 1 bit from 3rd octet and rest of them from 4th octet,
0 0 0 0 0 0 1 [0. 0 0 0 0 0 0 0 0] = 2.0,
0 0 0 0 0 0 1[1. 1 1 1 1 1 1 1 1 ] = 3.255.
because 2^(32-23) = 2^9,
3 : 0 0 0 0 0 0 1 1,
65 : 0 1 0 0 0 0 0 1.
9 means 1 bit from 3rd octet and rest of them from 4th octet,
0 0 0 0 0 0 1 [0. 0 0 0 0 0 0 0 0] = 2.0,
0 0 0 0 0 0 1[1. 1 1 1 1 1 1 1 1 ] = 3.255.
(1)
Colly said:
8 years ago
What is the broadcast for 10.1.1.1.8? Please, explain me.
Nana said:
8 years ago
Buy I thought the up address is class A. Am I right?
John said:
9 years ago
Good and enough explanation thanks to all.
Arunkumar said:
9 years ago
Hi @Davies.
The answer :10.255.255.255.
The answer :10.255.255.255.
Arunkumar said:
9 years ago
Option C is correct.
The subnet is 255.255.254.0 for10.16.3.0 because the CIDER value is 23.
The subnet is 255.255.254.0 for10.16.3.0 because the CIDER value is 23.
(1)
Aryan said:
9 years ago
255.255.254.0 is the subnet mask for the network right?
Then why not option C is correct?
Then why not option C is correct?
(1)
Davies said:
9 years ago
Please, what is the broadcast for 10.1.1.1.8?
Teshie said:
9 years ago
I don't understand how this will be the right answer.
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