Mechanical Engineering - Workshop Technology - Discussion
Discussion Forum : Workshop Technology - Section 2 (Q.No. 5)
5.
For obtaining a cup of diameter 25 mm and height 15 mm by drawing, the size of the round blank should be approximately
Discussion:
15 comments Page 1 of 2.
Jjp said:
1 decade ago
D = Square root of ((d*d)+(4dh)) = 46.09.
Gaurav said:
1 decade ago
Blank volume = Cup volume.
(pie*D^2/4)*t = pie*d*h*t+(pie*d^2/4)*t.
D = blank dia.
d = cup dia.
h = cup height.
t = thickness.
(pie*D^2/4)*t = pie*d*h*t+(pie*d^2/4)*t.
D = blank dia.
d = cup dia.
h = cup height.
t = thickness.
KRUNAL MODI said:
1 decade ago
Blank = (d^2+4dh)^1/2.
= (25^2+4*25*15)^1/2.
= (625+1500)^1/2.
= 46.09.
= (25^2+4*25*15)^1/2.
= (625+1500)^1/2.
= 46.09.
Sandeep dicholkar said:
10 years ago
Since the thickness of the sheet is not given, how do you calculate?
Devikiran said:
9 years ago
The Thickness of material gets canceled.
Surajit said:
9 years ago
The thickness of the blank and the cup won't be same. Am I right?
Sahil said:
9 years ago
What is the correct Formula? Please tell me.
Loki said:
8 years ago
I am not understanding this, please explain clearly.
S.rao said:
8 years ago
Formula please. Explain it.
(1)
Narayan said:
7 years ago
Blank dia = √{(d√) +(4dh)}.
(1)
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