Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 4 (Q.No. 40)
40.
One kg of ethylene (C2H4) requires 2 kg of oxygen and produces 22/7 kg of carbon dioxide and __________ kg of water or steam.
Discussion:
13 comments Page 1 of 2.
Ronak said:
1 decade ago
How we can get this answer?
Muniappan said:
1 decade ago
C12A-2 = 24.
H1A-4 = 4.
O16A-2 = 32.
28/28C2H4+32/28 O2 = 22/7+?.
1+32/28-22/7 = 9/7.
H1A-4 = 4.
O16A-2 = 32.
28/28C2H4+32/28 O2 = 22/7+?.
1+32/28-22/7 = 9/7.
Abdo said:
1 decade ago
I didn't understand this answer could anyone please help.
Murali said:
10 years ago
How 3 kg of ethylene and oxygen produce 22/7 kg of carbon dioxide it is wrong I think.
(1)
Senthil said:
10 years ago
Please help to solve this.
SUBHAJIT said:
9 years ago
C2H4 + 2O2 ----> 2CO2 +2H20,
28 kg + 32 kg ----> 88 kg + 36 kg,
28/28 + 32/28 ----> 88/28 + 36/28,
So, 9/7 kg is the answer.
28 kg + 32 kg ----> 88 kg + 36 kg,
28/28 + 32/28 ----> 88/28 + 36/28,
So, 9/7 kg is the answer.
(4)
Ritam said:
9 years ago
The reaction after balancing is as follows:
C2H4 + 3(O2) = 2(CO2) + 2(H2O),
Molecular mass of C2H4 = 28,
2(H2O) = 2 X 18 = 36,
Therefore, 1 kg of C2H4 produces 36/28 kg of H2O,
i.e 9/7 kg of water.
C2H4 + 3(O2) = 2(CO2) + 2(H2O),
Molecular mass of C2H4 = 28,
2(H2O) = 2 X 18 = 36,
Therefore, 1 kg of C2H4 produces 36/28 kg of H2O,
i.e 9/7 kg of water.
(5)
Rishabh Sirvaiya said:
9 years ago
But it requires 3.4 kg of oxygen not 2 Kg of oxygen.
Karan said:
9 years ago
@Rishabh.
Yes, completely agree. The equation is not getting balanced.
Yes, completely agree. The equation is not getting balanced.
Subhash mandal said:
8 years ago
But oxygen required 3.4 kg to produce 9/7 kg of water vapour.
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