Mechanical Engineering - Thermodynamics - Discussion

40. 

One kg of ethylene (C2H4) requires 2 kg of oxygen and produces 22/7 kg of carbon dioxide and __________ kg of water or steam.

[A]. 9/7
[B]. 11/7
[C]. 7/4
[D]. 11/4

Answer: Option A

Explanation:

No answer description available for this question.

Ronak said: (Jan 27, 2014)  
How we can get this answer?

Muniappan said: (Nov 2, 2014)  
C12A-2 = 24.

H1A-4 = 4.

O16A-2 = 32.

28/28C2H4+32/28 O2 = 22/7+?.

1+32/28-22/7 = 9/7.

Abdo said: (Sep 3, 2015)  
I didn't understand this answer could anyone please help.

Murali said: (Oct 24, 2015)  
How 3 kg of ethylene and oxygen produce 22/7 kg of carbon dioxide it is wrong I think.

Senthil said: (Jan 10, 2016)  
Please help to solve this.

Subhajit said: (Oct 2, 2016)  
C2H4 + 2O2 ----> 2CO2 +2H20,
28 kg + 32 kg ----> 88 kg + 36 kg,
28/28 + 32/28 ----> 88/28 + 36/28,
So, 9/7 kg is the answer.

Ritam said: (Oct 2, 2016)  
The reaction after balancing is as follows:
C2H4 + 3(O2) = 2(CO2) + 2(H2O),

Molecular mass of C2H4 = 28,
2(H2O) = 2 X 18 = 36,

Therefore, 1 kg of C2H4 produces 36/28 kg of H2O,

i.e 9/7 kg of water.

Rishabh Sirvaiya said: (Nov 12, 2016)  
But it requires 3.4 kg of oxygen not 2 Kg of oxygen.

Karan said: (Dec 26, 2016)  
@Rishabh.

Yes, completely agree. The equation is not getting balanced.

Subhash Mandal said: (Nov 13, 2017)  
But oxygen required 3.4 kg to produce 9/7 kg of water vapour.

Srikar said: (Jun 14, 2018)  
3 moles of oxygen is required to balance it.

Rajat said: (Mar 13, 2019)  
No, in balancing 6 oxygen is required to balance the equation and after calculating all the answer is coming 9/4. correct me, if I am wrong.

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