Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 1 (Q.No. 14)
14.
The pressure exerted by an ideal gas is __________ of the kinetic energy of all the molecules contained in a unit volume of gas.
Discussion:
32 comments Page 3 of 4.
Abishek said:
8 years ago
RT=KT AND RT=PV.
SO KE=3/2KT,
THEN KE = 3/2 PV.
Where v is unit volume =1.
So KE = 3/2 P(1).
SO KE=3/2KT,
THEN KE = 3/2 PV.
Where v is unit volume =1.
So KE = 3/2 P(1).
Suman said:
8 years ago
What is rt and kt?
Sathish said:
8 years ago
How did you find KE=3/2 KT?
WHAT IS MEAN BY "KT"?
WHAT IS MEAN BY "KT"?
(1)
Ganesh kumar said:
8 years ago
C is the right answer. Agree.
Harsh said:
7 years ago
Pressure excerpted by an ideal gas p equal to. 2/3 of kinetic energy per molecule.
Msdprasad said:
7 years ago
Kinetic theory of gases PV = 2/3KE.
(1)
Mykal baron said:
7 years ago
How can I get the weight of a substance?
Mykal baron said:
7 years ago
How can I get the weight of a substance?
Mykal baron said:
7 years ago
How can I get the weight of a substance?
Mykal baron said:
7 years ago
How can I get the weight of a substance?
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