Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 1 (Q.No. 14)
14.
The pressure exerted by an ideal gas is __________ of the kinetic energy of all the molecules contained in a unit volume of gas.
Discussion:
32 comments Page 1 of 4.
Anil shukla said:
1 decade ago
Pressure energy is related to macro level of system of gas. It is related to entire gas system. Whereas kinetic energy is energy at micro level energy, means at individual molecule level. And individual molecules having different K.E. , so how to compare them.
Mano said:
1 decade ago
Kinetic energy is related to Pressure. Kinetic energy is chance of energy from one form to another form by means of change of velocity of the particles. Pressure increases velocity decrease. I we can relate this connection.
Sach said:
7 years ago
Assuming monoatomic ideal gas, we have the degree of freedom as 3.
So U = KE = 3/2RT.
and RT = PV. (Ideal gas equation)
So,
KE = 3/2PV.
V = 1. (Given)
KE = 3/2P.
P = 2/3KI.
So U = KE = 3/2RT.
and RT = PV. (Ideal gas equation)
So,
KE = 3/2PV.
V = 1. (Given)
KE = 3/2P.
P = 2/3KI.
(8)
Krishna said:
1 decade ago
Theory of Kinetic energy gives us: PV = 1/3 NC^2.
Where NC^2 is root mean velocity.
Now if you multiply and divide by 2.
It gives => PV = 2/3*1/2NC^2 (K.E).
Where NC^2 is root mean velocity.
Now if you multiply and divide by 2.
It gives => PV = 2/3*1/2NC^2 (K.E).
Santosh said:
1 decade ago
Pressure does not depends on kinetic energy of molecules its only depend on momentum exchange of molecules.
Abishek said:
8 years ago
RT=KT AND RT=PV.
SO KE=3/2KT,
THEN KE = 3/2 PV.
Where v is unit volume =1.
So KE = 3/2 P(1).
SO KE=3/2KT,
THEN KE = 3/2 PV.
Where v is unit volume =1.
So KE = 3/2 P(1).
NIKHIL DESHMUKH said:
8 years ago
KE=3/2KT.
BUT PV=MRT FOR unit mass.
pv = rt.
So,
K.E = 3/2P.
Therefore,
p = 2/3 K.E.
BUT PV=MRT FOR unit mass.
pv = rt.
So,
K.E = 3/2P.
Therefore,
p = 2/3 K.E.
Yahadeepsinh Jadeja said:
1 decade ago
I did not get this question how can we compare the pressure and the kinetic energy?
Rahul sharma said:
9 years ago
KE = 3/2kT.
KT = RT.
and RT = PV.
So,
KE = 3/2PV.
V = 1.
KE = 3/2P.
P = 2/3KI.
KT = RT.
and RT = PV.
So,
KE = 3/2PV.
V = 1.
KE = 3/2P.
P = 2/3KI.
Harsh said:
7 years ago
Pressure excerpted by an ideal gas p equal to. 2/3 of kinetic energy per molecule.
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