Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 1 (Q.No. 14)
14.
The pressure exerted by an ideal gas is __________ of the kinetic energy of all the molecules contained in a unit volume of gas.
Discussion:
32 comments Page 3 of 4.
Krishna said:
1 decade ago
Theory of Kinetic energy gives us: PV = 1/3 NC^2.
Where NC^2 is root mean velocity.
Now if you multiply and divide by 2.
It gives => PV = 2/3*1/2NC^2 (K.E).
Where NC^2 is root mean velocity.
Now if you multiply and divide by 2.
It gives => PV = 2/3*1/2NC^2 (K.E).
Anil shukla said:
1 decade ago
Pressure energy is related to macro level of system of gas. It is related to entire gas system. Whereas kinetic energy is energy at micro level energy, means at individual molecule level. And individual molecules having different K.E. , so how to compare them.
Mano said:
1 decade ago
Kinetic energy is related to Pressure. Kinetic energy is chance of energy from one form to another form by means of change of velocity of the particles. Pressure increases velocity decrease. I we can relate this connection.
Ravi Uttamrao Chavan said:
1 decade ago
@Jitendra Harbolaji.
V^2 = 3RT/M, How this came?
V^2 = 3RT/M, How this came?
Imran Ali said:
1 decade ago
To understand this relation please read kinetic theory of gases.
Dhinesh said:
1 decade ago
How the pressure is related K.E and please give the relation?
Sid said:
1 decade ago
Use kinetic theory of gases PV = 2/3 KE.
Naisar said:
1 decade ago
Please anyone can explain this briefly?
Yahadeepsinh Jadeja said:
1 decade ago
I did not get this question how can we compare the pressure and the kinetic energy?
PRASHANT said:
1 decade ago
How to relate pressure and K.E?
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