Mechanical Engineering - Thermodynamics - Discussion

Discussion Forum : Thermodynamics - Section 6 (Q.No. 29)
29.
The kinetic energy per kg molecule of any gas at absolute temperature T is equal to (where Ru = Universal gas constant)
Ru x T
1.5 Ru x T
2 Ru x T
3 Ru x T
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
1 comments Page 1 of 1.

Sudarshan said:   1 decade ago
pv = 2/3K.E.
mrt = 2/3K.E.
K.E = 3/2mrt.
K.E = 1.5mrt.

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