Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 6 (Q.No. 12)
12.
The property of a working substance which increases or decreases as the heat is supplied or removed in a reversible manner, is known as
Discussion:
16 comments Page 1 of 2.
Seemab said:
4 years ago
When heat is increased, entropy will increase and when heat removes, entropy will decrease.
Overall entropy will remain Constant.
So, the entropy is correct in my point of view.
Overall entropy will remain Constant.
So, the entropy is correct in my point of view.
Ashok said:
6 years ago
Enthalpy increase or decrease if temperature increases or decreases but hear heat supplied or remove so entropy increase or decrease.
Rami said:
7 years ago
According to the second law of Thermodynamics.
ENTROPY is correct. So when heat removed 'S will still be positive or zero in the reversible process.
ENTROPY is correct. So when heat removed 'S will still be positive or zero in the reversible process.
Amr salama said:
7 years ago
By logic, during a reversible process, there is no change in enthalpy and internal energy.
Deepak said:
7 years ago
For enthalpy q=dh-vdp.
Thus if q is supplied this doesn't mean that dh will definitely increase because here heat is a summation of work and enthalpy may be work will increase and enthalpy will be decreased.
Thus if q is supplied this doesn't mean that dh will definitely increase because here heat is a summation of work and enthalpy may be work will increase and enthalpy will be decreased.
Paul said:
7 years ago
I think it is enthalpy. Because it measures the randomness.
Prasanta Pal said:
7 years ago
I think it is enthalpy or internal energy.
Because as the process is done by reversible manner so it is not entropy.
Because as the process is done by reversible manner so it is not entropy.
Waseem said:
8 years ago
Entropy is right answer as it is directly related to heat. While other properties are dependent on temperature. Eg. If in an isothermal heat addition enthalpy of the system remain constant.
Rakesh said:
8 years ago
All of them are the function of temperature except entropy, so the answer is C.
Karan said:
9 years ago
All the A, B & C options are correct because;
(a) Enthalpy is defined as the heat content in a system.
(b) According to 1st law, dQ = dU + dW.
(c) For a reversible process, dS = (dQ/T).
(a) Enthalpy is defined as the heat content in a system.
(b) According to 1st law, dQ = dU + dW.
(c) For a reversible process, dS = (dQ/T).
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