Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 1 (Q.No. 13)
13.
Workdone in a free expansion process is
Discussion:
18 comments Page 2 of 2.
Gaurang said:
10 years ago
Freely expanded that volume is maximum.
And differentiation of volume is zero than PdV is zero.
And differentiation of volume is zero than PdV is zero.
Ankit said:
10 years ago
There is not at all boundary available at either side so it is zero.
Hemesh Kumar said:
9 years ago
Vacuum works like on concept of continuum, in vacuum area, there is no resistive property exist, the expansion takes place continuously without any obstacle.
Shabeer said:
8 years ago
@Nithesh Borkar.
Can you please explain how pdv is not zero although dw (work done) is zero?
Can you please explain how pdv is not zero although dw (work done) is zero?
Lokesh said:
8 years ago
The free expansion process is like that of constant volume process and then the volume is constant, so we get work done is equal to zero by applying work done =integral pdv, in this equation.
And why all of them are thinking about the vacuum, if there may be some air, even physics says that vacuum cannot be created easily, so don't use a vacuum there.
And why all of them are thinking about the vacuum, if there may be some air, even physics says that vacuum cannot be created easily, so don't use a vacuum there.
(1)
Ashok said:
8 years ago
Then what do you mean by expansion if it constant volume?
(1)
Dhiraj said:
7 years ago
Work done in free expansion process is zero because free expansion means expansion against vacuum, so there is no resistance to move.
(2)
P. V. Lakshman said:
7 years ago
Free expansion means no pressure from the outside. So w=pdv, here when p= 0. Thus w=0.
(7)
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