Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 1 (Q.No. 13)
13.
Workdone in a free expansion process is
Discussion:
18 comments Page 1 of 2.
Lokesh said:
8 years ago
The free expansion process is like that of constant volume process and then the volume is constant, so we get work done is equal to zero by applying work done =integral pdv, in this equation.
And why all of them are thinking about the vacuum, if there may be some air, even physics says that vacuum cannot be created easily, so don't use a vacuum there.
And why all of them are thinking about the vacuum, if there may be some air, even physics says that vacuum cannot be created easily, so don't use a vacuum there.
(1)
Kanish jamwal said:
1 decade ago
Consider an insulated container divided into two parts, ideal gas is filled in one compartment other is evacuated. When partition is removed gas moved to vacuum there is change in volume but work done is zero vacuum has no resistance.
Nitin said:
1 decade ago
Work done in free expansion process is zero because there is no boundary move. (free expansion means expansion against vacuum and in this process enthalpy, internal energy and temperature is constant).
Hemesh Kumar said:
9 years ago
Vacuum works like on concept of continuum, in vacuum area, there is no resistive property exist, the expansion takes place continuously without any obstacle.
VIVEK said:
1 decade ago
Expansion of a gas in vacuum (pex = 0) is called free expansion.
Work done is zero during free expansion whether the process is reversible or irreversible.
Work done is zero during free expansion whether the process is reversible or irreversible.
Susanta said:
1 decade ago
Work done in free expansion process is zero because free expansion means expansion against vacuum, so there is no resistance to move.
Dhiraj said:
7 years ago
Work done in free expansion process is zero because free expansion means expansion against vacuum, so there is no resistance to move.
(2)
NITHESH BORKAR said:
1 decade ago
No resistance to offer so work done is zero only when we consider both gas and vacuum as a system, although PdV not equal to zero.
Sanjeev kumar jha said:
1 decade ago
No resistance due to no boundary so the work done is zero, the expansion takes place against the vacuum.
Gaurang said:
10 years ago
Freely expanded that volume is maximum.
And differentiation of volume is zero than PdV is zero.
And differentiation of volume is zero than PdV is zero.
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