Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 2 (Q.No. 23)
23.
The isothermal and isentropic processes are reversible non-flow processes.
Discussion:
12 comments Page 1 of 2.
Roy said:
1 decade ago
Disagree. Because a process can have constant entropy i.e. it can be isentropic if it is irreversible also. If the entropy decrease due to heat flow out of the system is equal due to entropy increase due to entropy generated within the system due to internal irreversibilities, then the net change of entropy of the irreversible process is zero i.e. the entropy is constant and the process is isentropic.
Anup Singh Biswakarma said:
9 years ago
All reversible adiabatic processes are isentropic but all isentropic process are not reversible. In irreversible process, when heat is rejected from the system, entropy change may be positive, negative or zero. Only when entropy change is zero the irreversible process is isentropic but when the entropy change is positive it is not isentropic.
Hardik Tiru said:
6 years ago
All the processes are nonflow processes. Like constant temp, pressure, volume, adiabatic, ploytropic expansion throttling process. The nonflow process is defined as the flow of work is varies with time so that's why this process is the nonflow process.
Vinoth said:
8 years ago
Isothermal process is reversible if only heat is transferred between finite temperature difference.
That's happening in Carnot cycle.
So, isothermal reversible or irreversible depends upon the source and system temperature difference.
That's happening in Carnot cycle.
So, isothermal reversible or irreversible depends upon the source and system temperature difference.
Prashant said:
1 decade ago
Tell me what are non flow processes.
I agree that isentropic is reversible one but I am sure that it is not valid for isothermal process.
I agree that isentropic is reversible one but I am sure that it is not valid for isothermal process.
Mohan said:
1 decade ago
@Kukku.
You are talking about ideal Carnot cycle in which isotropic and diabetic are same and I am agreeing with @Gopianand.
You are talking about ideal Carnot cycle in which isotropic and diabetic are same and I am agreeing with @Gopianand.
Dwaipayan said:
7 years ago
If so then why steam expansion in the turbine is assumed as isentropic or flow through the nozzle? Please explain to me.
Kukku said:
1 decade ago
Agree, because we know that both process are worked in Carnot cycle. And Carnot cycle is a reversible cycle.
Gopianand said:
1 decade ago
Non flow process means the fluid or working fluid does not flow, h=^u. Simply not with flow energy as PV.
Imran Ali said:
1 decade ago
Completely Disagree answer should be B. Above explanations are true.
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