Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 2 (Q.No. 23)
23.
The isothermal and isentropic processes are reversible non-flow processes.
Discussion:
12 comments Page 1 of 2.
Hardik Tiru said:
6 years ago
All the processes are nonflow processes. Like constant temp, pressure, volume, adiabatic, ploytropic expansion throttling process. The nonflow process is defined as the flow of work is varies with time so that's why this process is the nonflow process.
Dwaipayan said:
7 years ago
If so then why steam expansion in the turbine is assumed as isentropic or flow through the nozzle? Please explain to me.
Greeion said:
7 years ago
Isentropic = adiabatic + reversible.
Vinoth said:
8 years ago
Isothermal process is reversible if only heat is transferred between finite temperature difference.
That's happening in Carnot cycle.
So, isothermal reversible or irreversible depends upon the source and system temperature difference.
That's happening in Carnot cycle.
So, isothermal reversible or irreversible depends upon the source and system temperature difference.
Anup Singh Biswakarma said:
9 years ago
All reversible adiabatic processes are isentropic but all isentropic process are not reversible. In irreversible process, when heat is rejected from the system, entropy change may be positive, negative or zero. Only when entropy change is zero the irreversible process is isentropic but when the entropy change is positive it is not isentropic.
Mohan said:
1 decade ago
@Kukku.
You are talking about ideal Carnot cycle in which isotropic and diabetic are same and I am agreeing with @Gopianand.
You are talking about ideal Carnot cycle in which isotropic and diabetic are same and I am agreeing with @Gopianand.
Atul said:
1 decade ago
Disagree, because every isentropic process is not reversible.
Kukku said:
1 decade ago
Agree, because we know that both process are worked in Carnot cycle. And Carnot cycle is a reversible cycle.
Imran Ali said:
1 decade ago
Completely Disagree answer should be B. Above explanations are true.
Roy said:
1 decade ago
Disagree. Because a process can have constant entropy i.e. it can be isentropic if it is irreversible also. If the entropy decrease due to heat flow out of the system is equal due to entropy increase due to entropy generated within the system due to internal irreversibilities, then the net change of entropy of the irreversible process is zero i.e. the entropy is constant and the process is isentropic.
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