Mechanical Engineering - Thermodynamics - Discussion

Discussion Forum : Thermodynamics - Section 6 (Q.No. 9)
9.
The amount of heat required to raise the temperature of 1 kg of water through one Kelvin is called
specific heat at constant volume
specific heat at constant pressure
kilo-Joule
none of these
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
7 comments Page 1 of 1.

Saiteja said:   7 years ago
The answer must be kCal. Because the amount of heat required to raise the temperature of 1kg of water by 1k is 4.187kJ= 1kCal (since 1Cal=4.18J).

So the answer must be none of the above.

Ayan said:   9 years ago
The amount of heat required to raise the temperature of 1 kg of water through,
1 Kelvin = 1 KCal. = 4.2 KJoule.
1 cal. = 4.2 Joule.
1 kcal. = 4.2 KJoule.

Sakthi said:   9 years ago
The amount of heat required to raise the temperature of 1 kg of water through,

One Kelvin = kilo - Joule.

One degree celsius = kilo Calorie.
(1)

Rohit said:   5 years ago
I also agree that answer should be 1 kCal.

Jigisha said:   9 years ago
Please explain properly.

Fasil said:   5 years ago
Right, I agree @Saiteja.

DIXIT said:   10 years ago
Can anybody explain?

Post your comments here:

Your comments will be displayed after verification.