Mechanical Engineering - Theory of machines - Discussion
Discussion Forum : Theory of machines - Section 3 (Q.No. 34)
34.
The sensitiveness of the governor __________ as the speed range decreases.
Discussion:
18 comments Page 1 of 2.
Sudipto Ichigo said:
3 years ago
Option C is right.
Here, They are asking, what we need if the range of speed decreases but we want to have the same lift/ performance. Obviously higher sensitivity. Only if we have high sensitivity then only we can have the same life even when the range of speed decreases.
Here, They are asking, what we need if the range of speed decreases but we want to have the same lift/ performance. Obviously higher sensitivity. Only if we have high sensitivity then only we can have the same life even when the range of speed decreases.
Sankalp Singh said:
2 years ago
sensitivity(s)=2(N1-N2)/(N1+N2).
Assume N2 changes to N2-1 while N1 remains the same (a case where the range is decreased by 1).
So, the new sensitivity will be s+(s/2+1)/(N-1/2) where N = (N1+N2)/2,
Clearly, the sensitivity is increasing.
Assume N2 changes to N2-1 while N1 remains the same (a case where the range is decreased by 1).
So, the new sensitivity will be s+(s/2+1)/(N-1/2) where N = (N1+N2)/2,
Clearly, the sensitivity is increasing.
Lalit said:
3 years ago
Sensitiveness = mean speed/speed range.
Because isochronous governor.
It's sensitivity & to be infinite.
S = N1+N2/2(N1-N2).
SO ISOCHRONOUS GOVERNOR N1 = N2,
S=N+N/2(N-N) = 1/0= INFINITE.
Because isochronous governor.
It's sensitivity & to be infinite.
S = N1+N2/2(N1-N2).
SO ISOCHRONOUS GOVERNOR N1 = N2,
S=N+N/2(N-N) = 1/0= INFINITE.
Neeraj said:
8 years ago
How an isochronous governor attain infinite sensitivity?
If can only possible if:
Sensitivity = mean speed/range of speed.
As a range of speed for isoch. Governor is zero.
If can only possible if:
Sensitivity = mean speed/range of speed.
As a range of speed for isoch. Governor is zero.
Tanu said:
6 years ago
The correct answer is (C).
Because with mean speed is inversely proportional to the range of speed when we are not considering engine is not club with Governor.
Because with mean speed is inversely proportional to the range of speed when we are not considering engine is not club with Governor.
Deepak Sharma said:
7 years ago
Yes, the sensitivity of governor is a range of speed/mean speed.
But the mean speed also depends on the range of speed. That's why option C is correct.
But the mean speed also depends on the range of speed. That's why option C is correct.
Parth Shah said:
8 years ago
Sensitiveness of the governor.
= (N2 " N1)/N.
= 2(N2 " N1)/ (N1 + N2).
= 2(ω2 - ω1)/ (ω1 + ω2)
So answer should be B.
= (N2 " N1)/N.
= 2(N2 " N1)/ (N1 + N2).
= 2(ω2 - ω1)/ (ω1 + ω2)
So answer should be B.
Vanraj Gajarotar said:
9 years ago
Sensitiveness = Range of speed / Mean speed.
So sensitiveness is directly proportional to the range of speed so the answer is B.
So sensitiveness is directly proportional to the range of speed so the answer is B.
Vipin said:
10 years ago
Sensitiveness of the governor is directly proportional to the speed range.
Sensitiveness = range of speed / Mean speed.
Sensitiveness = range of speed / Mean speed.
ZXCVB said:
1 decade ago
Sensitiveness of governor = Range of speed/Mean speed.
So sensitiveness is directly proportional to speed range.
So sensitiveness is directly proportional to speed range.
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