Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 9 (Q.No. 39)
39.
In a thin cylindrical shell subjected to an internal pressure p, the ratio of longitudinal stress to the hoop stress is
Discussion:
7 comments Page 1 of 1.
Srilakshmi said:
8 years ago
Longitudinal stress =pd/4t.
Hoop stress=pd/2t where p is internal pressure and d is the diameter of thin cylindrical shell and t thickness.
So, pd/4t/pd/2t.
pd/4t*2t/pd answer is 1/2.
Hoop stress=pd/2t where p is internal pressure and d is the diameter of thin cylindrical shell and t thickness.
So, pd/4t/pd/2t.
pd/4t*2t/pd answer is 1/2.
Anish said:
6 years ago
Thanks @Srilakshmi.
Sanjoy said:
6 years ago
Thanks for explaining @Srilakshmi.
Akhilesh said:
6 years ago
Thanks @Srilakshmi.
ATUL said:
5 years ago
Thank you so much @Shrilakshmi.
KSRTC said:
4 years ago
Thanks @Sri.
Bittu said:
4 years ago
Thanks @Srila.
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