Mechanical Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 9 (Q.No. 39)
39.
In a thin cylindrical shell subjected to an internal pressure p, the ratio of longitudinal stress to the hoop stress is
1/2
3/4
1
1.5
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
7 comments Page 1 of 1.

Bittu said:   4 years ago
Thanks @Srila.

KSRTC said:   4 years ago
Thanks @Sri.

ATUL said:   5 years ago
Thank you so much @Shrilakshmi.

Akhilesh said:   6 years ago
Thanks @Srilakshmi.

Sanjoy said:   6 years ago
Thanks for explaining @Srilakshmi.

Anish said:   6 years ago
Thanks @Srilakshmi.

Srilakshmi said:   8 years ago
Longitudinal stress =pd/4t.
Hoop stress=pd/2t where p is internal pressure and d is the diameter of thin cylindrical shell and t thickness.
So, pd/4t/pd/2t.

pd/4t*2t/pd answer is 1/2.

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