Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 9 (Q.No. 6)
6.
A closely-coiled helical spring is cut into two halves. The stiffness of the resulting spring will be
Discussion:
11 comments Page 1 of 2.
MAHESH said:
1 year ago
Answer is A.
When you cut a closely coiled helical spring into two halves, each half will essentially behave like an independent spring. However, the stiffness of the resulting springs will not change. The stiffness, or spring constant, is determined by the material and the physical dimensions of the spring, such as the wire diameter, coil diameter, and number of coils, which remain unchanged when the spring is cut. Therefore, the stiffness of each resulting spring will be the same as the original spring.
When you cut a closely coiled helical spring into two halves, each half will essentially behave like an independent spring. However, the stiffness of the resulting springs will not change. The stiffness, or spring constant, is determined by the material and the physical dimensions of the spring, such as the wire diameter, coil diameter, and number of coils, which remain unchanged when the spring is cut. Therefore, the stiffness of each resulting spring will be the same as the original spring.
Jimit said:
5 years ago
N = n/2 so that cd^4/8D^3(n/2) = 2(cd^4/8D^3n) = 2K.
So, the stiffness is double.
So, the stiffness is double.
Ani said:
5 years ago
@Santosh.
If the springs are used in parallel connection then what will be the stiffness?
If the springs are used in parallel connection then what will be the stiffness?
Murali said:
6 years ago
(G.d^4)/64R^3n is the formula for stiffness. if n becomes half stiffness becomes 2(Gd^4)/(64R^3n). It means stiffness doubled.
Santosh Naganur said:
7 years ago
@Shekhar.
Obviously, the young's Modulus is same for a material but there is a two parts of same material therefore resultant stiffness will be k+k=2K.
Obviously, the young's Modulus is same for a material but there is a two parts of same material therefore resultant stiffness will be k+k=2K.
SHEKHAR said:
7 years ago
But if, the stiffness of a material is measured in terms of Young's modulus which itself is a materialistic property (and remains same for a material) then how the stiffness varies by varying the length?
Please explain.
Please explain.
Crdmistry said:
8 years ago
Cd^4 / 8 D^3 n this formula also A correct first one is wrong.
Dhavalo said:
9 years ago
Yes, Both are same. Agree @Shukla.
Saurabh shukla said:
10 years ago
Both formula are same dear C = D/d.
Amit said:
1 decade ago
Concept is correct but formula used is wrong.
Correct formula is [(G.d^4)/(64.R^3.n)].
Correct formula is [(G.d^4)/(64.R^3.n)].
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