Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 9 (Q.No. 6)
6.
A closely-coiled helical spring is cut into two halves. The stiffness of the resulting spring will be
Discussion:
11 comments Page 2 of 2.
Hari said:
1 decade ago
STIFFNESS OF SPRING = [(G*d)/(8* C^3 * N)].
Where N - No.of coils.
As you can see stiffness is inversely proportional to No of coils. When you cut the spring into half the stiffness will get doubled.
Where N - No.of coils.
As you can see stiffness is inversely proportional to No of coils. When you cut the spring into half the stiffness will get doubled.
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