Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 7 (Q.No. 21)
21.
The strain energy stored in a hollow circular shaft of outer diameter (D) and inner diameter (d) subjected to shear stress is
x Volume of shaft
x Volume of shaft
x Volume of shaft
x Volume of shaftDiscussion:
11 comments Page 1 of 2.
Venkat said:
9 years ago
How? Explain.
P Vinay said:
9 years ago
Using Equation, Strain energy, U = (1/2) TQ.
Obtain expression for T and Q from the torsion equation.
Q is the angle of twist in radians.
Obtain expression for T and Q from the torsion equation.
Q is the angle of twist in radians.
Ashley said:
9 years ago
It is D2 in denominator instead of D.
Mitesh morwal said:
8 years ago
Is should be D^2 in the denominator.
Shachindra Pandey said:
8 years ago
D^2 must be in the denominator.
Rajkotha said:
6 years ago
Option A is correct.
Ramya said:
6 years ago
Option 'A' is the correct answer.
Vijay said:
5 years ago
Expression for strain energy in shaft subjected to torsion. So Option D is correct.
True said:
5 years ago
For shear stress answer should be "B".
For torsion it's τ^2/4C (D^2+d^2/D^2) V.
For torsion it's τ^2/4C (D^2+d^2/D^2) V.
Vinod said:
5 years ago
Yes,
For shear stress answer should be "B".
For torsion, it's Ï„^2/4C (D^2+d^2/D^2) V.
For shear stress answer should be "B".
For torsion, it's Ï„^2/4C (D^2+d^2/D^2) V.
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