Mechanical Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 7 (Q.No. 21)
21.
The strain energy stored in a hollow circular shaft of outer diameter (D) and inner diameter (d) subjected to shear stress is
x Volume of shaft
x Volume of shaft
x Volume of shaft
x Volume of shaft
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
11 comments Page 1 of 2.

Atul Palsara said:   5 years ago
Torsion also produces shear stress but for shaft shearing due transverse load is not appropriate (as in the case of beams) that's why option "B" is not true here, it must be shearing by twisting moment of the shaft that's why option "D" is absolutely correct.

Vinod said:   5 years ago
Yes,

For shear stress answer should be "B".
For torsion, it's Ï„^2/4C (D^2+d^2/D^2) V.

True said:   5 years ago
For shear stress answer should be "B".

For torsion it's τ^2/4C (D^2+d^2/D^2) V.

Vijay said:   5 years ago
Expression for strain energy in shaft subjected to torsion. So Option D is correct.

Ramya said:   6 years ago
Option 'A' is the correct answer.

Rajkotha said:   6 years ago
Option A is correct.

Shachindra Pandey said:   8 years ago
D^2 must be in the denominator.

Mitesh morwal said:   8 years ago
Is should be D^2 in the denominator.

Ashley said:   9 years ago
It is D2 in denominator instead of D.

P Vinay said:   9 years ago
Using Equation, Strain energy, U = (1/2) TQ.

Obtain expression for T and Q from the torsion equation.

Q is the angle of twist in radians.


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