Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 46)
46.
The strain energy stored in a solid circular shaft subjected to shear stress (τ) is (where C = Modulus of rigidity for the shaft material)
x Volume of shaft
x Volume of shaft
x Volume of shaft
x Volume of shaftDiscussion:
38 comments Page 2 of 4.
Robiii said:
8 years ago
A given shaft which is subjected to shear stress so defini torsion will be developed no need to mention in a question.
Gaurav said:
8 years ago
The Answer will be D. I agree with the given answer.
Aakash said:
8 years ago
D is not a correct answer, Option B is the correct answer.
U = 1/2(T.θ)
U = 1/2(T^2L/GJ)
U = (τ^2/2G)Volume of shaft.
U = 1/2(T.θ)
U = 1/2(T^2L/GJ)
U = (τ^2/2G)Volume of shaft.
Joy Mandal said:
8 years ago
B is the correct answer. D is the strain energy due to torsion.
Teja Reddy said:
8 years ago
Answer is option B.
The strain energy stored in a solid circular shaft in torsion, subjected to shear stress (τ) , is:τ2/ 4G * Volume of the shaft.
The strain energy stored in a solid circular shaft in torsion, subjected to shear stress (τ) , is:τ2/ 4G * Volume of the shaft.
Abhilash said:
8 years ago
Option B is the correct answer.
Pradeep gk said:
8 years ago
D is correct answer because shaft is used for transmit the torque so when it rotates tortional stress is induced.
Galav said:
8 years ago
B is the right option.
Mohan said:
8 years ago
If it is purely shear stress than the answer is B.
Chahat sharma said:
8 years ago
Siimply, solve strain energy =0.5*T*θ.
Put T=(τ*J)/R.
And theta = (τ*L)/(C*R).
Note: separate volume as (π*d2*L).
You will get the same answer as D option.
Put T=(τ*J)/R.
And theta = (τ*L)/(C*R).
Note: separate volume as (π*d2*L).
You will get the same answer as D option.
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