Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 46)
46.
The strain energy stored in a solid circular shaft subjected to shear stress (τ) is (where C = Modulus of rigidity for the shaft material)
Discussion:
38 comments Page 4 of 4.
Vijay kumar said:
9 years ago
Torsion energy = 1/2 * T * angle of twist.
So, option D is correct.
So, option D is correct.
SARABJEET SINGH SANDHU said:
10 years ago
But torsion occurs due to shear force. So o0tion (D) is correct.
ABHIUSHEK said:
10 years ago
Answer D only applicable when the shaft is under torsion. So here it is not perfect and answer B is correct.
Mukesh kushwaha said:
10 years ago
The strain energy due to shear stress is answer B. Answer D is strain energy due to torsion.
Abhi said:
1 decade ago
Under direct shear stress option B is correct.
Manoj prasad said:
1 decade ago
Actually Q should be following way.
The strain energy stored in a solid circular shaft subjected to torsional stress (τ) is (where C = Modulus of rigidity for the shaft material),
then opt D.
OR
The strain energy stored in a solid circular shaft subjected to shear stress (τ) is (where C = Modulus of elasticity for the shaft material),
then opt B.
The strain energy stored in a solid circular shaft subjected to torsional stress (τ) is (where C = Modulus of rigidity for the shaft material),
then opt D.
OR
The strain energy stored in a solid circular shaft subjected to shear stress (τ) is (where C = Modulus of elasticity for the shaft material),
then opt B.
Ramesh Babu said:
1 decade ago
Yes option D is for strain energy stored in the material when it is subjected to torsional stress.
D' Nainesh said:
1 decade ago
Right answer is [B].
[D] is for strain energy stored in a material due to torsional stress. Here, shear stress is given for which B is true.
[D] is for strain energy stored in a material due to torsional stress. Here, shear stress is given for which B is true.
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