Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 8 (Q.No. 32)
32.
A simply supported beam 'A' of length l, breadth b, and depth d carries a central point load W. Another beam 'B' has the same length and depth but its breadth is doubled. The deflection of beam 'B' will be __________ as compared to beam 'A'.
Discussion:
13 comments Page 1 of 2.
Vikram said:
8 years ago
Can anybody explain this?
Bipul Ranjan said:
8 years ago
Deflection for SSB at central point load=wl^3/48Ei and deflection is inversely proportional to I(bd^3/12).
Hence deflection is also inversely proportional to breadth.
Db/Da = Ba/Bb.
= 1/2.
Hence deflection is also inversely proportional to breadth.
Db/Da = Ba/Bb.
= 1/2.
Debesh said:
8 years ago
It is double.
Mano said:
7 years ago
I think option C is correct.
S.k said:
7 years ago
Double is the correct answer.
Som said:
7 years ago
Deflection - pl/AE.
So, deflection is inversely proportional to area Db/Da=Aa/Ab=1/2.
So, deflection is inversely proportional to area Db/Da=Aa/Ab=1/2.
Debashis Das said:
6 years ago
Yes, Option C is correct.
Debashis Das said:
6 years ago
According to me, Option: C is correct.
Swapnil said:
6 years ago
Option b is correct. Because deflection is inversely proportional to flexural rigidity EI And I=bd^3/12.
Basavaraj said:
6 years ago
Option B is correct. Because deflection is inversely proportional to flexural rigidity EI And I=bd^3/12.
A=wl^3/48E*bd^3/12.
A=wl^3/4E*bd3,
B=wl^3/48E*2bd^3/12,
B=wl^3/8E*bd^3,
B/A=1/2.
Ans:B correct
A=wl^3/48E*bd^3/12.
A=wl^3/4E*bd3,
B=wl^3/48E*2bd^3/12,
B=wl^3/8E*bd^3,
B/A=1/2.
Ans:B correct
(1)
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