Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 6 (Q.No. 5)
5.
At the neutral axis of a beam, the shear stress is
Discussion:
24 comments Page 2 of 3.
Harpalsinh Jadeja said:
7 years ago
Shear stress zero in Neutral Axis.
Dheeraj said:
7 years ago
Yes, answer is right, shear stress =SAy'/Ib,
Where, S=shear force, A =area, y'=distance of centroid of area from NA. I=moi, b=width, Here, A and y' are varied wrt y, when you take the values of both in equation and after differenciating it, you will get, y=0, (consider a elementary area at a why distance from NA).
Where, S=shear force, A =area, y'=distance of centroid of area from NA. I=moi, b=width, Here, A and y' are varied wrt y, when you take the values of both in equation and after differenciating it, you will get, y=0, (consider a elementary area at a why distance from NA).
Prashant said:
7 years ago
Bending stress is zero.
But shear stress is maximum.
But shear stress is maximum.
Jitendra Kharwar said:
8 years ago
£max=1.5F/A=1.5F/bd.
So C is right.
So C is right.
Siddu hg said:
8 years ago
A is correct answer.
Joy said:
8 years ago
Shear stress is zero where the bending moment is maximum.
Ayan said:
8 years ago
Max at center. It is shear stress.
Ayan said:
8 years ago
I think the Answer is A.
Vikas Tomar said:
9 years ago
Maximum at center.
Rohit said:
9 years ago
The shear stress varies parabolically in the beam. It is maximum at the center and zero at fibres. The maximum shear force at neutral axis is given by s = 3F/2bd.
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